McGraw Hill Glencoe Geometry, 2012
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McGraw Hill Glencoe Geometry, 2012 View details
1. Areas of Parallelograms and Triangles
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Exercise 3 Page 783

The perimeter of a parallelogram is calculated by adding the lengths of its four sides. The area of a parallelogram is calculated by multiplying the base by the height.

Perimeter: 64cm
Area: 207.8cm^2

Practice makes perfect

A parallelogram is a quadrilateral where both of the pairs of opposite sides are parallel and congruent. Any side can be called the base of the parallelogram. Its height is the perpendicular distance between any two parallel bases. For the given parallelogram, we will find its perimeter and area one at a time.

Perimeter

Consider the given parallelogram.

We can see that the lengths of two nonparallel sides are 20cm and 12cm. Since opposite sides are congruent, the lengths of the other two sides are also 20cm and 12cm.

To find the perimeter, we add these four side lengths. Perimeter: 12+20+12+20=64cm

Area

The area of a parallelogram is the product of a base and its corresponding height. A=bh We can consider the side whose length is 12cm as the base. However, we need to find the height. To do so, we will pay close attention to the right triangle formed by the height, a side, and a part of a nonparallel side.

We can see that the measure of two of the interior angles of the triangle are 60^(∘) and 90^(∘). We can use the Triangle Angle Sum Theorem to find the measure of the third angle. 180- 90- 60=30^(∘) The third angle measures 30^(∘) and, therefore, we have a 30^(∘)-60^(∘)-90^(∘) triangle. In this type of triangle the length of the longer leg is sqrt(3)2 times the length of the hypotenuse. With this information, and knowing that the hypotenuse measures 20cm, we can find the length of the longer leg. Longer Leg: sqrt(3)/2 * 20=10sqrt(3)cm Therefore, the height of the parallelogram is 10sqrt(3)cm.

Now that we know that the base is 12cm and that the height is 10sqrt(3)cm, we can substitute these values in the formula for the area of a parallelogram.
A=bh
A=( 12)( 10sqrt(3))
A=207.846096...
A≈ 207.8
The area to the nearest tenth is 207.8cm^2.