McGraw Hill Glencoe Geometry, 2012
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McGraw Hill Glencoe Geometry, 2012 View details
1. Areas of Parallelograms and Triangles
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Exercise 4 Page 783

The perimeter of a parallelogram is calculated by adding the lengths of its four sides. The area of a parallelogram is calculated by multiplying the base by the height.

Perimeter: 60.1m
Area: 115m^2

Practice makes perfect

A parallelogram is a quadrilateral where both of the pairs of opposite sides are parallel and congruent. Any side can be called the base of the parallelogram. Its height is the perpendicular distance between any two parallel bases. For the given parallelogram, we will find its perimeter and area one at a time.

Perimeter

Consider the given parallelogram.

We can see that the length of a side is 23m. Therefore, the length of its opposite side is also 23m.

To find the perimeter we need to add the four side lengths. However, in our parallelogram we are missing two of them. To find them we will consider the right triangle formed by the height, one of the sides, and a part of a nonparallel side.

In this triangle the measures of two of the interior angles are 90^(∘) and 45^(∘). We can use the Triangle Angle Sum Theorem to find the measure of the third angle. 180- 90- 45=45^(∘) The measure of the third angle of the triangle is 45^(∘). Therefore, we have a 45^(∘)-45^(∘)-90^(∘) triangle. In this type of special triangle, the length of the hypotenuse is sqrt(2) times the length of a leg. Here, the length of a leg is 5m. Hypotenuse: sqrt(2) * 5= 5sqrt(2)m The hypotenuse of this triangle is the a side of the parallelogram. Also, recall that opposite sides are congruent in a parallelogram. Therefore, the length of the opposite side is also 5sqrt(2)m.

Now that we know the four side lengths of the parallelogram, we can add them to find its perimeter.
Perimeter=23+5sqrt(2)+23+5sqrt(2)
Simplify right-hand side
Perimeter=46+10sqrt(2)
Perimeter=60.142135...
Perimeter≈ 60.1
The perimeter of the parallelogram is approximately 60.1m.

Area

The area of a parallelogram is the product of a base and its corresponding height. We can consider the side whose length is 23m as the base. However, we need to find the height. To do so, we will pay close attention again to the right triangle formed on the right-hand side of the figure.

As previously mentioned, this is a 45^(∘)-45^(∘)-90^(∘) triangle. Since two of the angles are congruent, the triangle is an isosceles triangle and has two congruent sides. Therefore, the height is 5m.

Since we already know that the base is 23m, we can substitute these two values in the formula for the area of a parallelogram.
A=bh
A=(23)( 5)
A=115
The area is 115m^2.