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Identify the coordinates of the vertex.
y=x^2-4x-5
We want to write the equation of the given parabola. To do so, let's recall the vertex form of a quadratic function. y= a(x- h)^2+k In this expression, a, h, and k are either positive or negative constants. Let's start by identifying the vertex.
The vertex of this parabola has coordinates ( 2,-9). This means that we have h= 2 and k=-9. We can use these values to partially write our function. y= a(x-( 2))^2+(-9) ⇕ y= a(x-2)^2-9 We can see in the graph that the parabola opens upwards. Therefore, a will be a positive number. To find its value, we will use the given point that is not the vertex.
x= 0, y= - 5
Add terms
Calculate power
LHS+9=RHS+9
.LHS /4.=.RHS /4.
Rearrange equation
(a-b)^2=a^2-2ab+b^2
Calculate power and product
Subtract term