We will begin by defining the variables for the situation.
x: Number of times the price increasesy: Total profit
The total profit can be found by multiplying the price per video by the number of videos. We will organize the given information on a table and write the new price and new number of videos depending on
x.
Verbal Expression
|
Algebraic Expression
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Increasing the price x times ($)
|
0.25x
|
New price
|
2.25+0.25x
|
Decreasing the number of videos x times
|
100x
|
New number of videos
|
1400−100x
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Total profit is $y.
|
y=(2.25+0.25x)(1400−100x)
|
Now, we can write the equation in the form of
y=ax2+bx+c to determine its characteristics.
y=(2.25+0.25x)(1400−100x)
y=1400(2.25+0.25x)−100x(2.25+0.25x)
y=3150+350x−100x(2.25+0.25x)
y=3150+350x−225x−25x2
y=3150+125x−25x2
y=-25x2+125x+3150
The maximum value will be at the vertex. The
x-coordinate of the vertex tells us how many times we should increase the price to maximize the profit. We will use the formula for the axis of symmetry,
x=-2ab, to find the
x-coordinate of the vertex. In this case,
a=-25 and
b=125.
x=-2ab
x=-2(-25)125
x=--50125
x=50125
x=2.5
The
x value tells us that if the store increases the price
2.5 times, the income will be maximum. However, the number of increases must be a whole number. Therefore, the store should increase the price either
2 times or
3 times. We defined the new price on the table.
New price: 2.25+0.25x
By substituting
2 and
3 in the expression, we can find the possible prices.
Number of Decreases
|
2.25+0.25x
|
Price
|
2
|
2.25+0.25(2)
|
2.75
|
3
|
2.25+0.25(3)
|
3
|
Therefore, both $2.75 and $3 maximize the income.