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Are the variable terms all gathered on one side of the inequality?
{x|x ≥ 1/2}
Solving inequalities is done in the same way as solving equations, using inverse operations to isolate the variable. Just remember to reverse the inequality symbol when multiplying or dividing the inequality by a negative number.
LHS* 6 ≥ RHS * 6
Distribute 6
LHS+30x≥RHS+30x
LHS+4≥RHS+4
.LHS /32.≥.RHS /32.
a/b=.a /16./.b /16.
This tells us that all values greater than or equal to 12 satisfy the inequality. Knowing this, let's write the solution set. {x|x≥1/2}
We can check our solution by substituting a few arbitrary values into the given inequality. The value satisfies the inequality if the inequality remains true after substituting and simplifying.
x | 2x-4/6 ≥ - 5x+2 | Evaluate |
---|---|---|
-1 | 2( -1)-4/6 ≥ - 5( -1)+2 | -1≱ 7 |
1/2 | 2( 12)-4/6 ≥ - 5( 1/2)+2 | - 1/2 ≥ - 1/2 |
1 | 2( 1)-4/6 ≥ -5( 1)+2 | - 1/3 ≥ -3 |
We can conclude that, as long as x is greater than or equal to 12, the inequality is satisfied. Therefore our solution is correct.