McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
3. Solving Multi-Step Inequalities
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Exercise 45 Page 302

Are the variable terms all gathered on one side of the inequality?

{x|x ≥ 1/2}

Practice makes perfect

Solving inequalities is done in the same way as solving equations, using inverse operations to isolate the variable. Just remember to reverse the inequality symbol when multiplying or dividing the inequality by a negative number.

Solving the Inequality

We will start solving by using the Multiplication Property of Inequality to eliminate the fraction. From there, we will use the Addition and Division Properties of Inequality to isolate x on one side of the inequality.
2x-4/6 ≥ - 5x+2
2x-4 ≥ 6(- 5x+2 )
2x-4 ≥ - 30x + 12
32x-4 ≥ 12
32x ≥ 16
x ≥ 16/32
x ≥ 1/2

This tells us that all values greater than or equal to 12 satisfy the inequality. Knowing this, let's write the solution set. {x|x≥1/2}

Checking Our Solution

We can check our solution by substituting a few arbitrary values into the given inequality. The value satisfies the inequality if the inequality remains true after substituting and simplifying.

x 2x-4/6 ≥ - 5x+2 Evaluate
-1 2( -1)-4/6 ≥ - 5( -1)+2 -1≱ 7
1/2 2( 12)-4/6 ≥ - 5( 1/2)+2 - 1/2 ≥ - 1/2
1 2( 1)-4/6 ≥ -5( 1)+2 - 1/3 ≥ -3

We can conclude that, as long as x is greater than or equal to 12, the inequality is satisfied. Therefore our solution is correct.