McGraw Hill Glencoe Algebra 1, 2012
MH
McGraw Hill Glencoe Algebra 1, 2012 View details
3. Solving Multi-Step Inequalities
Continue to next subchapter

Exercise 53 Page 302

Draw the graphs of y= 13(4x+3) and y= 23x+2. When does the first graph lie above the second graph?

{x|x ≥ 32 }

Practice makes perfect

To solve the given inequality using a graphing calculator, we need to treat each side of the inequality symbol as its own individual equation. 1/3(4x+3) ≥2/3x+2 ⇓ ly=1/3(4x+3) y=2/3x+2 ⇓ ly=4/3x+1 y=2/3x+2 Then we can look for the values of x where the value of 43x+1 is greater than or equal to the value of 23x+2. In other words, we want to find the values of x where the graph of y= 43x+1 lies above the graph of y= 23x+2.

Graphing the Functions

Press Y= on the calculator to access the screen to input our functions.
Fönster med funktioner

To draw the graph, press the GRAPH button.

Fönster med en graf

Finding the Solution Set

We see that the graphs intersect at a point. The x-coordinate of this point can be found by pressing 2ND and then CALC.

Graffönster från TI-82

After selecting the intersect option, we choose the first and second curves. Then, the calculator asks for a guess where the intersection point might be. After that, it will calculate the exact point for us.

Window with a graph

The lines intersect at x=1.5, or x= 32. Tracing the lines on the calculator screen using the TRACE button, we can see that y= 43x+1 is the upper line after the intersection. Since the inequality is non-strict, it is also true at the point of intersection. This means that the given inequality holds true when x≥ 32. 4/3x+1≥2/3x+2 ⇔ x≥1.5 We can now write the solution set for our inequality. {x|x ≥ 32 }