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The phrase is no more than
can be expressed as ≤.
Example Variable: Let x represent the number.
Inequality: 10 ≤ 4(2x+3)
Solution Set: {x|x ≥ - 14}
To algebraically express a verbal inequality, we will need to translate the given information into mathematical symbols and operations.
is no more thancan be expressed as ≤. This symbol will be in the middle of our expression. ... ≤... On the left-hand side of the inequality symbol, we will translate any verbal expression that comes before
is no more than.
ten
10
On the right-hand side of the inequality symbol, we will translate any verbal expression that comes after is no more than.
If we let x represent a number,
we can form an algebraic expression. Note that x is an example variable — we can use any letter to represent it.
4times the sum of twice a number and three
4 ( 2 x + 3 )
Finally, we can bring these two expressions together to form the inequality.
10 ≤ 4(2x+3)
Distribute 4
LHS-12≤RHS-12
.LHS /8.≤.RHS /8.
a/b=.a /2./.b /2.
Rearrange inequality
We can check our solution by substituting a few arbitrary values into the inequality translated in the previous part. The value satisfies the inequality if the inequality remains true after substituting and simplifying.
x | 10 ≤ 4 (2x+3) | Evaluate |
---|---|---|
-1/2 | 10 ? ≤ 4(2( -1/2)+3) | 10 ≰ 8 |
-1/4 | 10 ? ≤ 4(2( - 1/4)+3) | 10 ≤ 10 |
-1/8 | 10 ? ≤ 4(2( - 1/8)+3) | 10 ≤ 11 |
We can conclude that, as long as x is greater than or equal to - 14, the inequality is satisfied. This means the solution set we have found is correct.