body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Glencoe Math: Course 3, Volume 2

GM

Glencoe Math: Course 3, Volume 2 View details

2. Volume of Cones

Continue to next subchapter

Exercise 33 Page 604

Use the formula for volume of a pyramid.

$90 cm^{3}$

Practice makes perfect

We are given a pyramid. Its base is a square with a side of $6$ centimeters. Its height is $7.5$ centimeters.

The volume of a pyramid can also be calculated using a known formula.

V = \frac{1}{3} B h

Here

V

is the volume,

B

is the area of the base, and

h

is the height. The area of the rectangle equals to the square of the length its side.

B = a^{2}

Here

a

is

6 .

We already have enough information to calculate the volume of the cone.

V = \frac{1}{3} B h

Rewrite $B$ as $a^{2}$

V = \frac{1}{3} a^{2} h

$a = 6$ , $h = 7.5$

V = \frac{1}{3} (6)^{2} (7.5)

▼

Evaluate right-hand side

Calculate power

V = \frac{1}{3} (36) (7.5)

Multiply

V = \frac{1}{3} (270)

MoveRightFacToNum

$\frac{a}{c} \cdot b = \frac{a \cdot b}{c}$

V = \frac{2 7 0}{3}

Calculate quotient

V = 90

The volume of the pyramid is

90

cubic centimeters.

Subchapter links

Guided Practice p.600

Independent Practice p.601-602

H.O.T. Problems p.602

Standardized Test Practice p.602-604

Extra Practice p.603

Common Core Review p.604