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Glencoe Math: Course 3, Volume 2

GM

Glencoe Math: Course 3, Volume 2 View details

2. Volume of Cones

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Exercise 18 Page 603

Use the formula for the volume of a cone.

Approximately $603.2 ft^{3}$

Practice makes perfect

Consider the given cone.

To find the volume, we can use the formula for the volume of a cone.

V = \frac{1}{3} π r^{2} h

Here,

r

is the radius and

h

is the height of the cone. We are given that the height of the cone is

16

feet. The radius of the base is

6

feet. Let's substitute these values into the formula and calculate the volume.

V = \frac{1}{3} π r^{2} h

$r = 6$ , $h = 16$

V = \frac{1}{3} π (6)^{2} (16)

▼

Simplify right-hand side

Calculate power

V = \frac{1}{3} π (36) (16)

Multiply

V = \frac{1}{3} π (576)

CommutativePropMult

Commutative Property of Multiplication

V = \frac{1}{3} (576 π)

MoveRightFacToNumOne

$\frac{1}{b} \cdot a = \frac{a}{b}$

V = \frac{5 7 6 π}{3}

Calculate quotient

V = 192 π

Use a calculator

V = 603.185790 \dots

Round to $1$ decimal place(s)

V \approx 603.2

The volume of the cone is

603.2

cubic feet.

Subchapter links

Guided Practice p.600

Independent Practice p.601-602

H.O.T. Problems p.602

Standardized Test Practice p.602-604

Extra Practice p.603

Common Core Review p.604