Glencoe Math: Course 3, Volume 2
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Glencoe Math: Course 3, Volume 2 View details
2. Volume of Cones
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Exercise 23 Page 603

Use the formula for the volume of a cone.

Approximately 15in.

Practice makes perfect

Consider the given cone. Its height is 8 inches and the volume is 471.24 cubic inches.

To find the diameter we want to find the radius first. We can use the formula for the volume of a cone. V= 13Ï€ r^2 h Here, r is the radius and h is the height of the cone. We are given that the height of the cone is 8 inches. The volume is 471.24 cubic inches. Let's substitute these values into the formula and solve for the radius r.

V=1/3Ï€ r^2 h
471.24=1/3Ï€ r^2 ( 8)
â–¼
Solve for r
471.24 = 1/3 (8)Ï€ r^2
1413.72 = 8Ï€ r^2
176.715 = π r^2
176.715/Ï€ = r^2
r^2 = 176.715/Ï€
r^2 = 56.250132...
r = sqrt(56.250132...)
r = 7.500009...
r ≈ 7.5

We found out that the approximate length of the radius is r=7.5. We can finally find the diameter.

d = 2r
d = 2( 7.5)
d = 15

Since the length of the radius was approximated, the diameter of 15 inches is also an approximation.