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Glencoe Math: Course 3, Volume 2

GM

Glencoe Math: Course 3, Volume 2 View details

2. Volume of Cones

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Exercise 27 Page 603

Use the formula for the volume of a cone.

Approximately $3.0 yd$

Practice makes perfect

We are given a cone.

To find the height, we can use the formula for the volume of a cone.

V = \frac{1}{3} π r^{2} h

Here,

r

is the radius and

h

is the height of the cone. We are given that the radius of the cone is

2.5

yards. The volume is

19.625

cubic yards. Let's substitute these values into the formula and solve for the height

h .

V = \frac{1}{3} π r^{2} h

$V = 19.625$ , $r = 2.5$

19.625 = \frac{1}{3} π (2.5)^{2} h

▼

Solve for

h

Calculate power

19.625 = \frac{1}{3} π (6.25) h

CommutativePropMult

Commutative Property of Multiplication

19.625 = \frac{1}{3} (6.25) π h

$LHS \cdot 3 = RHS \cdot 3$

58.875 = 6.25 π h

$LHS / 6.25 = RHS / 6.25$

9.42 = π h

$LHS / π = RHS / π$

\frac{9 . 4 2}{π} = h

Rearrange equation

h = \frac{9 . 4 2}{π}

Use a calculator

h = 2.998479 \dots

Round to $1$ decimal place(s)

h \approx 3.0

We found out that the height of the cone is approximately

3.0

yards.

Subchapter links

Guided Practice p.600

Independent Practice p.601-602

H.O.T. Problems p.602

Standardized Test Practice p.602-604

Extra Practice p.603

Common Core Review p.604