body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Glencoe Math: Course 3, Volume 2

GM

Glencoe Math: Course 3, Volume 2 View details

2. Volume of Cones

Continue to next subchapter

Exercise 26 Page 603

Use the formula for the volume of a cone.

Approximately 8.0in.

Practice makes perfect

We are given that the volume of a cone is 1205.76 cubic inches and the radius of the base is 12 inches.

To find the height, we can use the formula for the volume of a cone. V= 13π r^2 h Here, r is the radius and h is the height of the cone. We are given that the radius of the cone is 12 inches. The volume is 1205.76 cubic inches. Let's substitute these values into the formula and solve for the height h.

V=1/3π r^2 h

V= 1205.76, r= 12

1205.76=1/3π ( 12)^2 h

▼

Solve for h

Calculate power

1205.76 = 1/3 π (144) h

CommutativePropMult

Commutative Property of Multiplication

1205.76 = 1/3 (144)π h

MoveRightFacToNum

a/c* b = a* b/c

1205.76 = 144/3π h

Calculate quotient

1205.76 = 48 π h

.LHS /48.=.RHS /48.

25.12 = π h

.LHS /π.=.RHS /π.

25.12/π = h

Rearrange equation

h = 25.12/π

Use a calculator

h = 7.995944...

Round to 1 decimal place(s)

h ≈ 8.0

We found out that the height of the cone is approximately 8.0 inches.

Subchapter links

Guided Practice p.600

Independent Practice p.601-602

H.O.T. Problems p.602

Standardized Test Practice p.602-604

Extra Practice p.603

Common Core Review p.604