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| | 11 Theory slides |
| | 10 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
A monomial is an algebraic expression consisting of only one term. It is a product of powers of variables and a constant called the coefficient.
A single-term expression is a monomial only if all of its variables have whole numbers — non-negative and integers — as exponents. However, variables with positive exponents in the denominator are excluded because they are equivalent to a power in the numerator with the opposite exponent, according to the Quotient of Powers Property. Consider the following example. 5x/y^2 = 5xy^(- 2) In other words, if a variable in the denominator of an expression, it is not a monomial. The following are valid examples of monomials.
| Expression | Why It Is a Monomial |
|---|---|
| 5 | Any constant is a valid monomial. By the Zero Exponent Property, 5x^0=5. |
| 0 | The coefficient of a monomial can be 0. |
| - 2x^5 | The coefficient can be negative. |
| x^3y/5 | A monomial can have numbers in the denominator. |
Although they appear to be monomials at first glance, the single-term expressions in the following table do not satisfy the definition of a monomial.
| Expression | Why It Is Not a Monomial |
|---|---|
| 2x^(- 1) | The variables of a monomial cannot have negative integer exponents. |
| 4x^3/y | Monomials cannot have variables in the denominator. |
| 5 x^3y^(12) | The variables of a monomial must only have whole number exponents. |
Determine whether the given expression is a monomial.
The degree of a monomial is the sum of the exponents of its variable factors. If a variable has no exponent written in it, it is assumed to be 1. Additionally, all nonzero constants have a degree of 0. The constant 0 does not have a degree.
| Monomial | Degree |
|---|---|
| 3x | 1 |
| x^2 | 2 |
| 9x^3 | 3 |
| x^3y | 4 |
| 7 | 0 |
| a^3b^4c^5/13 | 12 |
| 0 | undefined |
Determine whether the given monomial is a linear expression.
Diego is having friends over this evening to watch movies and hang out. It would be great if they had some snacks while watching the movies! He suddenly remembers that he has a coupon in his wallet.
This coupon gives him 5 % off when buying snacks! Diego uses x to represent the total cost of the snacks he will buy. When he uses the coupon, 5 % of the sales price will be discounted from this total. x-0.05x=0.95x This means that Diego will only pay 95 % of the total.
0.95x The variable is x and the coefficient is 0.95. The variable x represents the normal price of the snacks Diego wants to buy. The coefficient 0.95 represents the total after a 5 % discount.
The only operation involved in this expression is the multiplication of the variable and the coefficient, so this expression is a monomial.
A monomial whose degree is 1 is a linear expression. Another linear expression can be created by either adding or subtracting a constant from a monomial of degree 1.
Start by finding the GCF of the linear expression. Rewrite each term as the product of its factors. 12x &= 2* 2 * 3 * x 4 &= 2* 2 The GCF of the initial expression is 2* 2= 4.
Next, rewrite each term of the initial expression as the product of the GCF and another factor. 12x &= 4* 3x 4 &= 4* 1 Now write the initial expression as follows. 12x+4 ⇕ [0.25em] 4* 3x+ 4* 1
Finally, use the Distributive Property to factor out the GCF. 4* 3x+ 4* 1 ⇕ [0.25em] 4( 3x + 1 ) The expression between the parentheses can to be examined to determine whether it is possible to continue the factorization. Here, the terms do not have any more common factors, so the linear expression is completely factored.
After grabbing the snacks for his get-together, Diego saw that the store had a sale on fruit.
Find the common factors of each term.
Consider the given linear expression and identify greatest common factor (GCF) of the terms.
The challenge presented at the start of the lesson can be solved by using the methods learned in this chapter. Consider the given linear expression. 18x+15 Begin by finding the factors of 18x and 15. 18x &= 2 * 3 * 3 * x 15 &= 3 * 5 Notice that they only share one factor, 3. This means their greatest common factor (GCF) is 3. Next, rewrite each term as a product involving the GCF. 18x &= 3 * 6x 15 &= 3 * 5 Finally, rewrite the expression by factoring out 3.
18x+15 &= 3* 6x + 3* 5 &= 3(6x+5)
A student tried to factor the greatest common factor (GCF) out of an algebraic expression. However, they got a wrong answer.
Let's start by taking a look at the given expression. 16x+36 We want to factor out the greatest common factor. Start by rewriting each term as a product of its factors. 16x &= 2 * 2 * 2 * 2 * x 36 &= 2 * 2 * 3 * 3 Notice that both terms have 2 as a factor two times. This means the GCF is 2* 2=4. The first step is correct! Next, rewrite each term as a product that involves the GCF. 16x &= 4 * 4x 36 &= 4 * 9 This lets us rewrite the original expression as follows. 16x+36 = 4 * 4x + 4 * 9 This step is also correct! Finally, factor out the GCF. 16x+36 = 4 * (4x+9) This is the step where the student made the mistake. They wrote 36 instead of 9 after factoring out the GCF. This means the answer is Step III.
We already found the correct answer by factoring out the GCF in Part A. Let's take a look at it once more.
4(4x+9)
Let's begin by taking a look at the original expression. 6a+18 We want to know which of the options from the pool are correct factorizations of the above expression. We can verify each one by expanding the products using the Distributive Property. Let's start with the first option.
The first option resulted in the original expression. This means it is a correct factorization. We can expand the rest of the options in a similar way.
| Factored Form | Use the Distributive Property | Simplify |
|---|---|---|
| 2(3a+9) | 2* 3a + 2 * 9 | 6a+18 |
| 2(6a+3) | 2* 6a + 2 * 3 | 12a+6 |
| 4(2a+14) | 4 * 2a + 4 * 14 | 8a+56 |
| 6(a+3) | 6 * a + 6 * 3 | 6a+18 |
| 3(2a+6) | 3 * 2a + 3* 6 | 6a+18 |
The correct factorizations are 2(3a+9), 6(a+3), and 3(2a+6).
Let's begin by taking a look at the original expression. 24x+40 We want to know which of the options from the pool is not a correct factorization of the above expression. We can verify each one by expanding the products using the Distributive Property. Let's start with the first option.
The first option resulted in the original expression, meaning that it is a correct factorization. We can expand the rest of the options in a similar way.
| Factored Form | Use the Distributive Property | Simplify |
|---|---|---|
| 2(12x+20) | 2* 12x + 2 * 20 | 24x+40 |
| 4(6x+10) | 4* 6x + 4 * 10 | 24x+40 |
| 6(4x+6) | 6 * 4x + 6 * 6 | 24x+36 |
| 8(3x+5) | 8 * 3x + 8 * 5 | 24x+40 |
The incorrect factorization is 6(4x+6).