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In this exercise, we will examine Ron-Jon's incorrect solution when he tried to find the slope of a line. Let's begin by writing the slope formula.
$slope=runrise ⇔m=x_{2}−x_{1}y_{2}−y_{1} $
In the formula, $m$ represents the slope, and $(x_{1},y_{1})$ and $(x_{2},y_{2})$ represent points that lie on the line. Let's find the slope by ourselves and compare our results to determine the mistake Ron-Jon made. To do so, we will substitute $(5,4)$ and $(-1,16)$ for $(x_{1},y_{1})$ and $(x_{2},y_{2}),$ respectively.
Right away we can see Ron-Jon's error. The points were wrongly substituted into the formula. Basically, he calculated
The correct slope is $-2.$

run over riserather than

rise over run.Let's continue and find the correct slope.

$m=-1−516−4 $

SubTermsSubtract terms

$m=-612 $

MoveNegNumToFracPut minus sign in front of fraction

$m=-612 $

CalcQuotCalculate quotient

$m=-2$