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We see that a is the measure of an inscribed angle and b is the measure of a central angle. Both of these angles have the same intercepted arc.
The measure of the central angle is the same as the measure of the intercepted arc. By the Inscribed Angle Theorem the measure of the inscribed angle is half the measure of its intercepted arc. This gives us the following relationship between a and b. a = 1/2 b Both a and b are positive, so this relationship tells us that a is less than b.
The diagram shows a triangle with a and b as two of its sides. The angle opposite a has a measure of 62^(∘), but we do not know the measure of the angle opposite b. Once we know it, we can use the Law of Sines to relate a to b. So, first, let's find the measure of the last angle in our triangle. Let's call the measure of this angle x.
Add terms
LHS-132^(∘)=RHS-132^(∘)
LHS * a=RHS* a
.LHS /.sin 48^(∘) /b..=.RHS /.sin 48^(∘) /b..
\a/b/c= a * c/b
a* b/c=a/c* b
Rearrange equation
Use a calculator
s= 6
Calculate power
a/c* b = a* b/c
a/b=.a /4./.b /4.
a/1=a
Use a calculator
Round to 1 decimal place(s)
A square with a side length s has an area s^2. In our case s= 4, so the area equals 4^2 = 16 square units. This means b = 16.
We found that a ≈ 15.6 and b = 16. This means a is less than b.