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Core Connections Integrated II, 2015

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Core Connections Integrated II, 2015 View details

2. Section 12.2

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Exercise 84 Page 677

The volume of a square-based pyramid is the product of its base area and height divided by 3.

Diagram:

Volume: 324 cm^3

Practice makes perfect

Let's start by drawing the described pyramid. Note that the base is a square, which means it has four congruent sides.

The volume of a square-based pyramid is the product of its base area and height divided by 3. V=1/3 B h ⇔ V=1/3 s^2 h Let's substitute the height and side of the base area into the formula and evaluate.

V=1/3s^2h

s= 9, h= 12

V=1/3( 9)^2( 12)

▼

Evaluate right-hand side

MoveRightFacToNumOne

1/b* a = a/b

V=(9)^2(12)/3

Simplify quotient

V=(9)^2(4)

Calculate power

V=81(4)

Multiply

V=324

Subchapter links

12.2.1 Using Geometry to Calculate Probabilities p.670-673

12.2.2 Choosing a Model p.676-679

12.2.3 The Golden Ratio p.685-688

12.2.4 Some Challenging Probability Problems p.696-699