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We want to find the value of a using the fact that the pentagram can be inscribed in a circle. We know that angles at all of the five outer vertices of a pentagram are congruent to each other. Now, let's notice that the pentagram divides the circumference of the circle into 5 congruent arcs.
Since the measure of the arc going around the entirety of a circle is 360^(∘), the measure of each of the smaller arcs is 360^(∘) / 5 = 72^(∘). Now, a is the measure of the inscribed angle that has one of the smaller arcs as its intercepted arc. By the Inscribed Angle Theorem the value of a is half that of the intercepted arc. a = 72^(∘)/2 = 36^(∘)
Let's start by finding the value of b.
In Part A, we found that a = 36^(∘). Also, since all angles at the outer vertices of the pentagram are congruent, all of them have a measure of 36^(∘).
Now, notice that we can find the measure of the reflexive angle adjacent to the b angle. The reflexive angle is the only missing angle of a concave quadrilateral.
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LHS-108^(∘)=RHS-108^(∘)
We know that b = 108^(∘). Since vertical angles have equal measures, the angle opposite the b angle also has the measure of 108^(∘).
Now, since all angles at the outer vertices of the pentagram are congruent, we have a regular pentagon within the pentagram. All interior angles of this pentagon are congruent. We conclude that c = 108^(∘).
Finally, let's find the measure of d.
Let's notice that d is the measure of an angle adjacent to one of the interior angles of the inner pentagon. These two angles form a straight line so the sum of their measures equals 180^(∘). d + 108^(∘) = 180^(∘) ⇒ d = 72^(∘)