Exercise 9 Page 399

Let's use the same coordinate plane given in the example. Since the park is 3 miles east and 4 miles south of your apartment, its coordinates are P(3,-4).

To find the distance between the park and the school, we need to determine the distance between the points P and S.

To find PS, we should use the Distance Formula.

PS = sqrt((x_2-x_1)^2 + (y_2-y_1)^2)

SubstitutePoints

Substitute ( 4,-1) & ( 3,-4)

PS = sqrt(( 4- 3)^2 + ( -1-( -4))^2)

SubTerm

Subtract term

PS=sqrt(1^2+(-1-(-4))^2)

SubNeg

a-(- b)=a+b

PS=sqrt(1^2+3^2)

CalcPow

Calculate power

PS=sqrt(1+9)

AddTerms

Add terms

PS=sqrt(10)

UseCalc

Use a calculator

PS=3.16227...

RoundDec

Round to 1 decimal place(s)

PS≈3.2

The distance between your school and the park is approximately 3.2 miles.