Big Ideas Math Integrated I, 2016
BI
Big Ideas Math Integrated I, 2016 View details
2. Writing Equations in Point-Slope Form
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Exercise 33 Page 176

Practice makes perfect
a Let's first identify some points on the function.
Number of Stickers x Cost, y
1000 1 225
2000 2 225+80=305
3000 3 305+80=385
Each additional 1000 stickers cost $80. This tells us that the rate of change is constant and that this is a linear function. Let's recall the point-slope form of a linear function. y-y_1= m(x-x_1) Here m represents the slope of the line and (x_1,y_1) is a point on the line. Let's find the slope by substituting the points ( 1, 225) and ( 2, 305) into the Slope Formula.
m = y_2-y_1/x_2-x_1
m=305- 225/2- 1
m=80/1
m=80
The function has a slope of 80. We can now write an equation for the line by substituting 80 for m and the point ( 1, 225) for ( x_1, y_1) into the formula. y- y_1&= m(x- x_1) &⇓ y- 225&= 80(x- 1) To get an equation that represents the total cost as a function of the number of stickers, we need to rewrite this into slope-intercept form.
y-225=80(x-1)
â–Ľ
Solve for y
y-225=80x-80
y=80x+145
We now have an equation that represents the total cost of the stickers. y=80x+145
b To find the total cost of 9000 stickers, we have to substitute x= 9 in the function we found in Part A, as x is the number of thousands of stickers.
y=80x+145
y=80( 9)+145
â–Ľ
Evaluate right-hand side
y=720+145
y=865
The cost of 9000 stickers is $865.