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Least Money: Sibling A
Lowest Spender: Sibling A
Last: Sibling A
Let's consider the graph that illustrates how Sibling A spends the money.
From the graph, we see that the y-intercept occurs at (0, 80), which means this sibling received $ 80.
Let's view the function that tells how Sibling B spends money. y=-22.5x+ 90 From the function, we see that the y-intercept occurs at (0, 90). This sibling received $ 90.
In the table we do not have an ordered pair where x=0. But since the sibling spends the money at a constant rate, we can use the rate of change to find the y-intercept. We will use the Slope Formula and the points ( 1, 100) and ( 2, 75) to calculate the rate of change.
Substitute ( 1,100) & ( 2,75)
Subtract terms
a/1=a
Sibling C has a rate of change of - 25, which corresponds to spending $25 each week. After one week of spending the sibling had $100 left. This means that the sibling must have started with $ 125.
Now we can summarize and determine who received what amount of money. Sibling A:& $ 80 ( least) Sibling B:& $ 90 Sibling C:& $ 125 ( most)
To find the slope for Sibling A we can use the points from the graph, ( 2, 50) and ( 4, 20), and substitute them into the Slope Formula.
Substitute ( 2,50) & ( 4,20)
Subtract terms
Calculate quotient
For Sibling B, we have a function where we can identify the slope by looking at the coefficient of x. y= - 22.5x+90 The slope for Sibling B is - 22.5, indicating a spending rate of $ 22.50 per week.
In Part A we determined the rate of change for Sibling C to be - 25. As such, the spending rate is $ 25 per week.
Let's summarize what we have found. Sibling A:& $ 15 a week ( least) Sibling B:& $ 22.50 a week Sibling C:& $ 25 a week ( most)
Sibling A spends $ 15 a week and starts out with $ 80. This means we can model their spending behavior with a linear function with a slope of - 15 and a y-intercept of 80.
y=- 15x+80
y= 0
LHS+15x=RHS+15x
.LHS /15.=.RHS /15.
Round to 1 decimal place(s)
Sibling A runs out of money after about 5.3 weeks.
We know that Sibling B has $25 left at the end of 4 weeks. Since they spend $25 a week, the remaining money will last one more week. Thus, Sibling B runs out of money after 5 weeks.
We have a linear function that tells us how much money Sibling C has at a given time. y=- 22.5x+90 We find the x-intercept by substituting 0 for y and solving for x.
y= 0
LHS+22.5x=RHS+22.5x
.LHS /22.5.=.RHS /22.5.
Sibling C runs out of money at the end of week 4.
Let's summarize when each of the siblings run out of money. Sibling A:& 5.3 weeks ( last) Sibling B:& 5 weeks Sibling C:& 4 weeks ( first)