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BI
Big Ideas Math Integrated I, 2016
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1. Angles of Triangles
1. Solving Linear Equations
p. 1-49
11 Subchapters
2. Solving Linear Inequalities
p. 51-99
12 Subchapters
3. Graphing Linear Functions
p. 101-161
12 Subchapters
4. Writing Linear Functions
p. 163-213
12 Subchapters
5. Solving Systems of Linear Equations
p. 215-269
13 Subchapters
6. Exponential Functions and Sequences
p. 271-327
12 Subchapters
7. Data Analysis and Displays
p. 329-375
11 Subchapters
8. Basics of Geometry
p. 377-437
12 Subchapters
9. Reasoning and Proofs
p. 439-493
11 Subchapters
10. Parallel and Perpendicular Lines
p. 495-539
11 Subchapters
11. Transformations
p. 541-583
10 Subchapters
12. Congruent Triangles
p. 585-653
14 Subchapters
Start
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Communicate Your Answer
p. 587
2 Solutions
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Monitoring Progress
p. 588-591
4 Solutions
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Exercises
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Exercise
56
Page
594
Page
594
Hint & Answer
Solution
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We know that AB ≅ GH.
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Progress overview
From the two figures, we see that AB ≅ GH. This means we can equate the expressions of these segments. AB ≅ GH: 5y-8=3y
Since the equation only contains y as a variable, it can be solved.
5y-8=3y
SubEqn
LHS-3y=RHS-3y
2y-8=0
AddEqn
LHS+8=RHS+8
2y=8
DivEqn
.LHS /2.=.RHS /2.
y=4
When we know that y= 4 we can substitute this into the expression for GH: GH: 3( 4)=12
Theorems About Triangles
Level 1 exercises - Theorems About Triangles
Level 2 exercises - Theorems About Triangles
Level 3 exercises - Theorems About Triangles
Subchapter links
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Communicate Your Answer
p.587
3
Communicate Your Answer
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(Page 587)
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Monitoring Progress
p.588-591
Monitoring Progress
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Monitoring Progress
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Monitoring Progress
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Exercises
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