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We know that AB ≅ GH.
12
From the two figures, we see that AB ≅ GH. This means we can equate the expressions of these segments. AB ≅ GH: 5y-8=3ySince the equation only contains y as a variable, it can be solved.
LHS-3y=RHS-3y
LHS+8=RHS+8
.LHS /2.=.RHS /2.
When we know that y= 4 we can substitute this into the expression for GH: GH: 3( 4)=12