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The distance traveled is the same irrespective of the variable used.
Isolate g on one side.
Substitute 6 hours into one of the equations.
55t=20g
g=11/4t
330 miles on 16.5 gallons of gas
The distance d we travel in a car is expressed by two different equations. However, the traveled distance is the same in each case. So we can equate the given equations in order to relate g and t.
Let's solve this equation for g.
.LHS /20.=.RHS /20.
Rearrange equation
a/b=.a /5./.b /5.
If we travel 6 hours, then t=6. We can find the amount of gasoline the car uses to travel that distance using the equation found in Part B.
t= 6
a/c* b = a* b/c
Calculate quotient
This means that we need 16 and a half gallons of gasoline for our trip. Furthermore, if we want to calculate how far we can travel, we need to use one of the equations given in the original problem. Let's use the second one.
We can travel 330 miles.