body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Big Ideas Math Integrated I, 2016

BI

Big Ideas Math Integrated I, 2016 View details

5. Rewriting Equations and Formulas

Continue to next subchapter

Exercise 34 Page 41

Practice makes perfect

a To solve the formula for

m,

let's isolate

m

on one side.

d = \frac{m}{V}

$LHS \cdot V = RHS \cdot V$

d V = m

Rearrange equation

m = d V

b The density of the pyrite is given as

5.01

g / cm^{3}

and its volume

1.2

cm^{3}

. In order to find the mass

m,

we substitute these values into the rewritten formula.

m = d V

$d = 5.01$ , $V = 1.2$

m = 5.01 \cdot 1.2

Multiply

m = 6.012

Therefore, the mass is

6.012

grams.

Subchapter links

Communicate Your Answer p.35

Monitoring Progress p.36-39

Exercises p.40-42