Exercise 28 Page 40

To solve the given formula for h, we will use the Properties of Equality to apply inverse operations on the equation. Remember, only like terms can be combined.

S=2π r^2+2π rh

SubEqn

LHS-2π r^2=RHS-2π r^2

S-2π r^2=2π rh

DivEqn

.LHS /2π r.=.RHS /2π r.

S-2π r^2/2π r=h

RearrangeEqn

Rearrange equation

h=S-2π r^2/2π r