Big Ideas Math Geometry, 2014
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Big Ideas Math Geometry, 2014 View details
2. Areas of Circles and Sectors
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Exercise 41 Page 608

The area of a semicircle is half the area of a circle. Note that the area of the unshaded region is equal to the area of the larger semicircle minus the area of the triangle. You will need to use the Pythagorean Theorem.

See solution.

Practice makes perfect

Let a, b, and c be the radii of each semicircle. Then, the diameters of the semicircles are 2a, 2b, and 2c, respectively. Let's label these radii and the shaded areas.

Since we have a right triangle, we can apply the Pythagorean Theorem and write the following equation. (2c)^2 = (2a)^2 + (2b)^2 ⇓ c^2 = a^2 + b^2

The area of the right triangle is equal to one-half the product of the length of the legs. A_3 = 1/2* 2a* 2b ⇓ A_3 = 2ab Now, let's find the area of the three semicircles. Keep in mind that their areas are half the area of the corresponding circle.

Radius Area of Semicirle
a A_(S_1) = 1/2Ď€ a^2
b A_(S_2) = 1/2Ď€ b^2
c A_(S_3) = 1/2Ď€ c^2
From the diagram, we can see that the area of the unshaded region is equal to the area of the semicircle with radius c minus the area of the triangle. A_(unshaded) = A_(S_3) - A_3 Let's substitute the corresponding values into the equation above and simplify it.
A_(unshaded) = A_(S_3) - A_3
A_(unshaded) = 1/2Ď€ c^2 - 2ab
Finally, to find the area of the two shaded crescents we subtract the unshaded area from the sum of the areas of the two smaller semicircles. A_1 + A_2_(crescents) = A_(S_1) + A_(S_2) - A_(unshaded) As before, let's substitute and simplify the corresponding values into the equation above.
A_1 + A_2 = A_(S_1) + A_(S_2) - A_(unshaded)
A_1 + A_2 = 1/2Ď€ a^2 + 1/2Ď€ b^2 - A_(unshaded)
â–Ľ
Simplify right-hand side
A_1 + A_2 = 1/2Ď€ (a^2 + b^2) - A_(unshaded)
A_1 + A_2 = 1/2Ď€* c^2 - ( 1/2Ď€ c^2 - 2ab)
A_1 + A_2 = 1/2Ď€ c^2 + 2ab - 1/2Ď€ c^2
A_1 + A_2 = 2ab
A_1 + A_2 = A_3
We have proven that the sum of the areas of the two shaded crescents is equal to the area of the triangle.