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The area of a semicircle is half the area of a circle. Note that the area of the unshaded region is equal to the area of the larger semicircle minus the area of the triangle. You will need to use the Pythagorean Theorem.
See solution.
Let a, b, and c be the radii of each semicircle. Then, the diameters of the semicircles are 2a, 2b, and 2c, respectively. Let's label these radii and the shaded areas.
Since we have a right triangle, we can apply the Pythagorean Theorem and write the following equation.
(2c)^2 = (2a)^2 + (2b)^2
⇓
c^2 = a^2 + b^2
| Radius | Area of Semicirle |
|---|---|
| a | A_(S_1) = 1/2Ï€ a^2 |
| b | A_(S_2) = 1/2Ï€ b^2 |
| c | A_(S_3) = 1/2Ï€ c^2 |
From the diagram, we can see that the area of the unshaded region is equal to the area of the semicircle with radius c minus the area of the triangle. A_(unshaded) = A_(S_3) - A_3 Let's substitute the corresponding values into the equation above and simplify it.
Finally, to find the area of the two shaded crescents we subtract the unshaded area from the sum of the areas of the two smaller semicircles. A_1 + A_2_(crescents) = A_(S_1) + A_(S_2) - A_(unshaded) As before, let's substitute and simplify the corresponding values into the equation above.
A_(S_1)= 1/2Ï€ a^2, A_(S_2)= 1/2Ï€ b^2
Factor out 1/2Ï€
a^2+b^2= c^2, A_(unshaded)= 1/2Ï€ c^2 - 2ab
-(b-a)=a-b
Subtract terms
2ab= A_3
We have proven that the sum of the areas of the two shaded crescents is equal to the area of the triangle.