2. Areas of Circles and Sectors
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Walk: 90^(∘)
Other: 36^(∘)
Walk: about 3.14 in^2
Other: about 1.26 in^2
Method | Percent of students |
---|---|
Bus | 65 % |
Walk | 25 % |
Other | 10 % |
Method | Percent of students |
---|---|
Bus | 65 % |
Walk | 25 % |
Other | 10 % |
Because 65 % of the students get to school using a bus, the central angle is equal to 65 % multiplied by 360^(∘). 65 % * 360^(∘) = 0.65* 360^(∘) = 234^(∘) From the above, the sector that will represent the percent of students going to school in bus has a central angle of 234^(∘). Similarly, let's find the central angles of the other two sectors.
Method | Percent of students | Central angle |
---|---|---|
Bus | 65 % | 64 % * 360^(∘) = 234^(∘) |
Walk | 25 % | 25 % * 360^(∘) = 90^(∘) |
Other | 10 % | 10 % * 360^(∘) = 36^(∘) |
Finally, let's make a graph representing the data in the table.
To find the area of a sector, we will use the formula below. Area of a sector = mAB/360^(∘)* π r^2 Let's substitute the corresponding values into the formula above.
Method | Percent of students | Central Angle | Area (in^2) |
---|---|---|---|
Bus | 65 % | 234^(∘) | A_1 = 234^(∘)/360^(∘)* π (2)^2 ≈ 8.17 |
Walk | 25 % | 90^(∘) | A_2 = 90^(∘)/360^(∘)* π (2)^2 ≈ 3.14 |
Other | 10 % | 36^(∘) | A_3 = 36^(∘)/360^(∘)* π (2)^2 ≈ 1.26 |