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A = π(6)^2 ⇒ A = 36π in^2 According to the given information, this pizza is enough for three people. By dividing this area by 3, we will find how much pizza is enough for each person. 36π/3 = 12π in^2 Now we want to buy pizzas for 8 people, so the amount of pizza needed is 8* 12π or 96π in^2. Let's find the area of the pizzas of different sizes.
Diameter (in) | Radius (in) | Area (in^2) | Cost ($) |
---|---|---|---|
10 | 5 | P_1 = 25Ď€ | 6.99 |
14 | 7 | P_2 = 49Ď€ | 12.99 |
Next, let's consider the different ways of buying the pizzas so that it is enough for the 8 people.
Pizzas Required | Amount of Pizza (in^2) | Cost ($) |
---|---|---|
4 small pizzas | 100Ď€ | 27.96 |
2 small pizzas and 1 large | 99Ď€ | 26.97 |
2 large pizzas | 98Ď€ | 25.98 |
As we can see, in order to spend as little money as possible we must buy two 14-inch pizzas.
Size | Area (in^2) | Cost ($) |
---|---|---|
Small | P_1 = 25Ď€ | 6.99 |
Large | P_2 = 49Ď€ | 12.99 |
In this part we want to buy three pizzas. In the following table, we will write different ways to do it with the total costs.
Number of Pizzas | Area (in^2) | Cost ($) | Enough Pizza? |
---|---|---|---|
3 small | 75Ď€ | 20.97 | No |
2 small and 1 large | 99Ď€ | 26.97 | Yes |
1 small and 2 large | 123Ď€ | 32.97 | Yes |
3 large | 147Ď€ | 38.97 | Yes |
The first option is the cheapest one, but it will not be enough pizza for the 8 people. Therefore, we conclude that the second option is the cheaper one.
Size | Radius | Circumference |
---|---|---|
Small | 5 | C_1 = 2Ď€(5) = 10Ď€ |
Large | 7 | C_2 = 2Ď€(7) = 14Ď€ |
Let's write some options we have to buy enough pizzas for the 8 people along with the total circumference.
Number of Pizzas | Area (in^2) | Circumference (in) |
---|---|---|
4 small | 100Ď€ | 40Ď€ |
2 small and 1 large | 99Ď€ | 34Ď€ |
1 small and 2 large | 123Ď€ | 38Ď€ |
2 large | 98Ď€ | 28Ď€ |
From the options in the table above, we can see that the option that gives as much of the thick outer crust as possible is the first one.