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If two equivalent logarithmic expressions have the same base, then the arguments must be equal.
x=4
We want to solve an equation involving more than one logarithm. To do so, we will use the Product Property of Logarithms. log_b mn = log_b m + log_b n First, we will isolate the logarithm that contains the variable. Then, we can use the above property to isolate the variable from the logarithm.
log_2(m) + log_2(n)=log_2(mn)
m=log_2(2^m)
Calculate power
Equate arguments
Distribute x
LHS-8=RHS-8
Rewrite -2x as 2x-4x
Factor out x
Factor out -4
Factor out (x+2)
Use the Zero Product Property
(I): LHS-2=RHS-2
(II): LHS+4=RHS+4
To check for extraneous solutions, we will substitute both -2 and 4 for x in the given equation one at a time.
x= -2
Subtract term
The argument of a logarithmic function cannot be negative, so both log_2(-2) and log_2(-4) are undefined, and -4 is an extraneous solution. Let's now check for x=4.
x= 4
Subtract term
log_2(2) = 1
Calculate logarithm
Add terms
Since substituting 4 for x in the given equation produces a true statement, x=4 is the solution to our equation.