When solving an equation we should choose any method that makes things easier for us. In this exercise, we will show how to solve different kinds of and .
a. Solving 16^x =2
Note that this equation uses 16 as a base for the exponential expression in the left-hand side, while the one on the right-hand uses 2. Since 16= 2^4, we can rewrite the equation so that both sides have the same base and we can equate the exponents. This because equal powers with same bases have same exponents. Let's give it a try.
16^x =2
(2^4)^x =2
2^(4x) =2
2^(4x) =2^1
4x = 1
x = 1/4
b. Solving 2^x =4^(2x+1)
This case is similar to the previous one, but here we have two exponential expressions on each side. Since 4=2^2, we can rewrite the right-hand side and simplify so that both exponential expressions have the same base. We can then equate the exponents.
2^x =4^(2x+1)
2^x =(2^2)^(2x+1)
2^x =2^(4x+2)
x = 4x +2
- 3x = 2
x = - 2/3
c. Solving 2^x =3^(x+1)
In this equation the bases involved do not have anything in common, as they are different
prime numbers. We can use both sides as arguments of a logarithm and use the to solve it.
2^x =3^(x+1)
log(2^x) = log(3^(x+1))
xlog(2) = (x+1)log(3)
xlog(2) = xlog(3)+ log(3)
0= xlog(3)-xlog(2)+ log(3)
0 = x (log(3)-log(2))+ log(3)
0 = x log ( 32)+ log(3)
- log(3) = x log ( 32)
- log(3)/log ( 32) = x
x = - log(3)/log ( 32)
d. Solving log x =1/2
In this case we can use the appropriate to undo the . Since the notation is just log, we know that this is a and the base is 10.
log x = 12
10^(log x) =10^(12)
x = 10^(12)
x = sqrt(10)
e. Solving ln x = 2
Once more, we can use the appropriate exponential function to undo the logarithmic function. Since the notation is ln we know that this is a and the base is the
f. Solving log_3 x = 3/2
Similarly as in the two previous cases we can use an exponential function to undo the logarithmic function. In this case the notation log_3 lets us know that we should use 3 as a base.
log_3 x = 3/2
3^(log_3 x) = 3^(32)
x = 3^(32)
x = sqrt(3^3)
x = sqrt(27)