6. Solving Exponential and Logarithmic Equations
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You are given everything you need to use point-slope form.
y-2 = -2 (x-3)
y- y_1= m(x- x_1) In this format, m represents the slope and the point ( x_1, y_1) lies on the graph of the line. We are given the point ( 3, 2) and the slope m = -2, so we have everything we need to create a point-slope form equation. Let's now substitute x_1= 3, y_1= 2, and m= -2. y-y_1=m(x-x_1) ⇕ y- 2= -2(x- 3)