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If two equivalent logarithmic expressions have the same base, then the arguments must be equal.
x=4
We want to solve an equation involving more than one logarithm. To do so, we will use the Product Property of Logarithms. log_b mn = log_b m + log_b n First, we will isolate the logarithm that contains the variable. Then, we can use the above property to isolate the variable from the logarithm.
log_4(m) + log_4(n)=log_4(mn)
Distribute x
m=log_4(4^m)
Calculate power
Equate arguments
To check for extraneous solutions, we will substitute both -16 and 4 for x in the given equation one at a time.
x= -16
Add terms
The argument of a logarithmic function cannot be negative, so both log_4(-4) and log_4(-16) are undefined, and -16 is an extraneous solution. Let's now check for the x=4.
x= 4
Add terms
log_4(m) + log_4(n)=log_4(mn)
Calculate logarithm
Since substituting 4 for x in the given equation produces a true statement, x=4 is a solution to our equation.