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| | 14 Theory slides |
| | 9 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
A group of people at a restaurant is waiting for a table for a family dinner. Waiters began adding tables one by one until the entire group was seated as requested.
Sometimes a quantity is unknown or its value may change. If this is the case, the best way to represent this quantity is using a variable.
A variable is a symbol used to represent an unknown quantity. Often, variables represent fixed but unknown numbers. Variables are usually denoted with letters such as x. x+1=8 In this case, x is a variable in an equation. Solving this equation for x will identify the value of x that makes the equation true. x+1=8 ⇔ x=7 Alternatively, a variable can be used to represent a quantity that changes. Izabella's income varies depending on the number of hours she works. She receives a fixed salary of$100 per week plus$4 per hour. In this case, Izabella's weekly income could be different every week, depending on the number of hours she works. Therefore, the use of a variable is appropriate. Let x be the hours that Izabella works in a week. Her income can be written by adding the fixed $100 to the $4 per hour.
Izabella's Weekly Income 4x+100There are many real-life situations that can be modeled by combining numbers and variables in algebraic expressions. A special case of algebraic expressions are linear expressions.
A linear term is an algebraic expression that includes a coefficient multiplied by a variable with an exponent of one. A linear expression is an expression that includes at least one linear term and any constant terms. No other type of terms may be included. The most common form of a linear expression is given below.
In this expression, a and b are real numbers, with a≠ 0. To completely understand the definition of a linear expression, some important concepts will be be broken down. Consider the example linear expression x-5y+2.
| x-5y+2 | ||
|---|---|---|
| Concept | Explanation | Example |
| Term | Parts of an expression separated by a +or -sign. |
x, - 5y, 2 |
| Coefficient | A constant that multiplies a variable. If a coefficient is 1, it does not need to be written due to the Identity Property of Multiplication. | 1, - 5 |
| Linear Term | A term that contains exactly one variable whose exponent is 1. | x, - 5y |
| Constant Term | A term that contains no variables. It consists only of a number with its corresponding sign. | 2 |
The following table shows some examples of linear and non-linear expressions.
| Linear Expressions | Non-linear Expressions |
|---|---|
| 3x | 5 |
| -5y+1 | 2xy-3 |
| 3x-1/2y+2 | 1/x-2 |
| π x+6y | 5x^2+x-1 |
It is important to keep in mind that before classifying an expression, it must be written in simplest form. 3x + 4 -2x + 9 - x = 13
The expression 3x + 4 -2x + 9 - x looks like a linear expression, but the result after simplifying is 13, which is a constant and therefore not a linear expression.Ramsha, Tiffaniqua, Zosia, and some of their friends are spending the summer at math camp. One of their first lessons is about identifying parts of linear expressions. They are given the following table to fill in based on the linear expressions in the top row.
| 6x-1 | sqrt(2)+x | -2x+3-9y | |
|---|---|---|---|
| Term(s) | |||
| x-term | |||
| y-term | |||
| Linear Term(s) | |||
| Coefficient(s) | |||
| Constant Term |
Help them fill in the table.
| 6x-1 | sqrt(2)+x | -2x+3-9y | |
|---|---|---|---|
| Term(s) | 6x and -1 | sqrt(2) and x | -2x, 3, and -9y |
| x-term | 6x | x | -2x |
| y-term | - | - | -9y |
| Linear Term(s) | 6x | x | -2x and -9y |
| Coefficient(s) | 6 | 1 | -2 and -9 |
| Constant Term | -1 | sqrt(2) | 3 |
| 6x-1 | sqrt(2)+x | -2x+3-9y | |
|---|---|---|---|
| Term(s) | 6x and - 1 | sqrt(2) and x | - 2x, 3, and - 9y |
| x-term | |||
| y-term | |||
| Linear Term(s) | |||
| Coefficient(s) | |||
| Constant Term |
The x-term is the term that contains the variable x.
| 6x-1 | sqrt(2)+x | -2x+3-9y | |
|---|---|---|---|
| Term(s) | 6x and - 1 | sqrt(2) and x | - 2x, 3, and - 9y |
| x-term | 6x | x | - 2x |
| y-term | |||
| Linear Term(s) | |||
| Coefficient(s) | |||
| Constant Term |
Similarly, the y-term is the term that contains the variable y. In this case, the first two expressions do not have a y-term.
| 6x-1 | sqrt(2)+x | -2x+3-9y | |
|---|---|---|---|
| Term(s) | 6x and - 1 | sqrt(2) and x | - 2x, 3, and - 9y |
| x-term | 6x | x | - 2x |
| y-term | - | - | - 9y |
| Linear Term(s) | |||
| Coefficient(s) | |||
| Constant Term |
The linear terms are the terms that contain only one variable, raised to the power of 1.
| 6x-1 | sqrt(2)+x | -2x+3-9y | |
|---|---|---|---|
| Term(s) | 6x and - 1 | sqrt(2) and x | - 2x, 3, and - 9y |
| x-term | 6x | x | - 2x |
| y-term | - | - | - 9y |
| Linear Term(s) | 6x | x | - 2x and - 9y |
| Coefficient(s) | |||
| Constant Term |
Next, the coefficients are the numbers that multiply a variable. When there is no number in front of a variable, the coefficient is 1.
| 6x-1 | sqrt(2)+x | -2x+3-9y | |
|---|---|---|---|
| Term(s) | 6x and - 1 | sqrt(2) and x | - 2x, 3, and - 9y |
| x-term | 6x | x | - 2x |
| y-term | - | - | - 9y |
| Linear Term(s) | 6x | x | - 2x and - 9y |
| Coefficient(s) | 6 | 1 | - 2 and - 9 |
| Constant Term |
Finally, the constant term is any term without a variable.
| 6x-1 | sqrt(2)+x | -2x+3-9y | |
|---|---|---|---|
| Term(s) | 6x and - 1 | sqrt(2) and x | - 2x, 3, and - 9y |
| x-term | 6x | x | - 2x |
| y-term | - | - | - 9y |
| Linear Term(s) | 6x | x | - 2x and - 9y |
| Coefficient(s) | 6 | 1 | - 2 and - 9 |
| Constant Term | - 1 | sqrt(2) | 3 |
Select the required parts of the given linear expressions.
Ramsha is on the second day of a hiking excursion at math camp. On the first day, she hiked from base camp to the first station.
Her current distance from base camp, in miles, is given by the following linear expression. Distance From the Base Camp 1.5x+10 Here, x is the number of hours Ramsha walks on the second day.
Note that 1.5x+10 represents a distance and the units of each term are miles. However, the units of x are hours. This gives a clue of the units of the coefficient 1.5.
In order to get rid of hours
and end up with miles,
the units of the coefficient must be miles per hour.
Therefore, the coefficient represents speed, or more precisely, the speed at which Ramsha walks.
In the previous example, an expression modeling a real-life scenario was provided. However, most of the time such expressions are not provided and must instead be created. The use of inductive reasoning can help with this process.
Inductive reasoning is the process of finding patterns in specific observations and writing a conclusion or conjecture. Since the conjecture is based on observations, it might be false. For example, suppose an observer notices that all the birds around them are white. The observer might inductively reason that all birds in the world are white, which is not true.
| n | Number of Cubes | |
|---|---|---|
| Figure 1 | 0 | 1+ 3* 0 = 1 |
| Figure 2 | 1 | 1+ 3* 1 = 4 |
| Figure 3 | 2 | 1+ 3* 2 = 7 |
| Figure 4 | 3 | 1 + 3* 3 = 10 |
| Figure 121 | 120 | 1+3* 120 = 361 |
At the end of the math camp, the students all visit an amusement park. Tiffaniqua did so well at camp that she won a coupon that allows her entire friend group to go on rides for x dollars per ride. By the end of the day, the group has gone on 11 rides and each person has eaten one hot dog.
The price of a hot dog is d dollars and the group is formed by k people, including Tiffaniqua.
Write an expression that represents the total amount of money the group paid.
In the previous two examples, each situation was represented by an algebraic expression. There are some cases where writing an expression is not enough to model a situation. In such cases, an equation might be required.
An equation is a type of mathematical relation that indicates that two quantities are equal. Equations often contain one or more unknowns values called variables. Some examples are shown below.
Equations always contain an equals sign, while expressions do not. In fact, an equation can be seen like a statement that connects two expressions with an equals sign.
When learning about equations, a good first step is to start with linear equations, which involve only one variable.
A linear equation is an equation with at least one linear term and any number of constants. No other types of terms may be included. Linear equations in one variable have the following form, where a and b are real numbers and a≠ 0.
ax+b=0 or ax = b
Zosia wants to go shopping after camp, but she realizes that she spent too much money at the amusement park. She decides to start saving money and go shopping when she has $25 saved up. She puts $15 in her piggy bank and plans to add $0.50 every day.
Let t be the number of days Zosia has been saving money. Write an equation that models the moment when her savings reaches $25.
0.5t + 15 = 25
Now that she has money saved up, Zosia is finally going to the mall. At the candy store, she buys 3 bags containing the same number of candies. The store also gives her 2 free candy samples. When she arrives home, she opens the bags and counts a total of 17 candies.
This lesson discussed linear expressions and linear equations, as well as how to use inductive reasoning to create them. Countless real-life situations can be modeled by algebraic expressions and equations. Consider again the challenge presented at the beginning of the lesson.
For each subsequent table, two more people are seated.
A linear expression can be used to model this situation. ax+ b Here, a= 2 because adding a table will add two more seated people. It can be noted that there will be always 2 people at the ends of the big table.
Therefore, it can be said that b= 2. With this, the expression is complete. Number of people= 2x+ 2
Kriz has $1000 saved. They need a total of $2000 to buy a new gaming laptop.
In order to reach this amount, they plan to save $50 per week from their part-time job. Let w be the number of weeks that Kriz has saved. Write an equation that can be used to find after how many weeks Kriz will reach their goal.
To start writing an equation, we need to put the equality sign in the middle. ... = ... Kriz saves $50 each week, so we can find their new savings by multiplying 50 by the number of weeks passed since they started saving money. Let's put this on the left-hand side of the equation! 50w = ... This money will be used for their new laptop. Since Kriz started with $1000, we can find the total amount of money saved by adding these amounts. 1000+50w = ... Since Kriz aims to buy a $2000 gaming laptop, we will finish our equation by setting this expression equal to 2000. 1000+50w=2000
LaShay is making cookies for her cousins. She bakes the cookies in small batches of 5.
After baking all the batches, she eats two cookies. Write an equation that can be used to find the total number of cookies T that LaShay is going to give to her cousins. Write the answer in terms of the number of batches b she made.
To start writing an equation, we need to put the equality sign in the middle. ... = ... LaShay bakes 5 cookies in each batch, so we multiply 5 by the number of batches b she made. Let's put this on the right-hand side of the equation! ... = 5b These cookies will be given to LaShay's cousins, but not before she eats two of them. This means that we will subtract 2 from the total amount of cookies LaShay baked. ... = 5b-2 Finally, we write the total amount of cookies to be given to her cousins on the left-hand side of the equation. T=5b-2
Magdalena wants to play 2 games of golf this weekend.
A packet of practice golf balls contains 4 balls. Magdalena wants 20 balls for each game of golf she will play. Write an equation that can be used to find the number of packets p of golf balls that Magdalena should buy.
To start writing an equation, we need to put the equality sign in the middle. ... = ... We know from the exercise that a single pack of golf balls contains 4 balls. This means that if Magdalena buys p packs, she will have 4 p golf balls. Let's write that on the right-hand side of the equality. ... = 4 p This value should be equal to the number of golf balls Magdalena wants for each game, 20, multiplied by the number of games she will play, 2. 20* 2=4p This can be simplified by performing the multiplication on the left-hand side of the equation. 40=4p