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| 14 Theory slides |
| 9 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here is a recommended reading before getting started with this lesson.
Sometimes a quantity is unknown or its value may change. If this is the case, the best way to represent this quantity is using a variable.
There are many real-life situations that can be modeled by combining numbers and variables in algebraic expressions. A special case of algebraic expressions are linear expressions.
A linear term is an algebraic expression that includes a coefficient multiplied by a variable with an exponent of one. A linear expression is an expression that includes at least one linear term and any constant terms. No other type of terms may be included. The most common form of a linear expression is given below.
In this expression, a and b are real numbers, with a=0. To completely understand the definition of a linear expression, some important concepts will be be broken down. Consider the example linear expression x−5y+2.
x−5y+2 | ||
---|---|---|
Concept | Explanation | Example |
Term | Parts of an expression separated by a +or −sign. |
x, -5y, 2 |
Coefficient | A constant that multiplies a variable. If a coefficient is 1, it does not need to be written due to the Identity Property of Multiplication. | 1, -5 |
Linear Term | A term that contains exactly one variable whose exponent is 1. | x, -5y |
Constant Term | A term that contains no variables. It consists only of a number with its corresponding sign. | 2 |
The following table shows some examples of linear and non-linear expressions.
Linear Expressions | Non-linear Expressions |
---|---|
3x | 5 |
-5y+1 | 2xy−3 |
3x−21y+2 | x1−2 |
πx+6y | 5x2+x−1 |
Ramsha, Tiffaniqua, Zosia, and some of their friends are spending the summer at math camp. One of their first lessons is about identifying parts of linear expressions. They are given the following table to fill in based on the linear expressions in the top row.
6x−1 | 2+x | -2x+3−9y | |
---|---|---|---|
Term(s) | |||
x-term | |||
y-term | |||
Linear Term(s) | |||
Coefficient(s) | |||
Constant Term |
Help them fill in the table.
6x−1 | 2+x | -2x+3−9y | |
---|---|---|---|
Term(s) | 6x and -1 | 2 and x | -2x, 3, and -9y |
x-term | 6x | x | -2x |
y-term | - | - | -9y |
Linear Term(s) | 6x | x | -2x and -9y |
Coefficient(s) | 6 | 1 | -2 and -9 |
Constant Term | -1 | 2 | 3 |
When there is no number in front of a variable, the coefficient is 1. The x- and y-terms are the terms that contain the variables x and y, respectively.
Start by finding the terms of each expression. Recall that the terms are the parts separated by addition or subtraction signs.
6x−1 | 2+x | -2x+3−9y | |
---|---|---|---|
Term(s) | 6x and -1 | 2 and x | -2x, 3, and -9y |
x-term | |||
y-term | |||
Linear Term(s) | |||
Coefficient(s) | |||
Constant Term |
The x-term is the term that contains the variable x.
6x−1 | 2+x | -2x+3−9y | |
---|---|---|---|
Term(s) | 6x and -1 | 2 and x | -2x, 3, and -9y |
x-term | 6x | x | -2x |
y-term | |||
Linear Term(s) | |||
Coefficient(s) | |||
Constant Term |
Similarly, the y-term is the term that contains the variable y. In this case, the first two expressions do not have a y-term.
6x−1 | 2+x | -2x+3−9y | |
---|---|---|---|
Term(s) | 6x and -1 | 2 and x | -2x, 3, and -9y |
x-term | 6x | x | -2x |
y-term | - | - | -9y |
Linear Term(s) | |||
Coefficient(s) | |||
Constant Term |
The linear terms are the terms that contain only one variable, raised to the power of 1.
6x−1 | 2+x | -2x+3−9y | |
---|---|---|---|
Term(s) | 6x and -1 | 2 and x | -2x, 3, and -9y |
x-term | 6x | x | -2x |
y-term | - | - | -9y |
Linear Term(s) | 6x | x | -2x and -9y |
Coefficient(s) | |||
Constant Term |
Next, the coefficients are the numbers that multiply a variable. When there is no number in front of a variable, the coefficient is 1.
6x−1 | 2+x | -2x+3−9y | |
---|---|---|---|
Term(s) | 6x and -1 | 2 and x | -2x, 3, and -9y |
x-term | 6x | x | -2x |
y-term | - | - | -9y |
Linear Term(s) | 6x | x | -2x and -9y |
Coefficient(s) | 6 | 1 | -2 and -9 |
Constant Term |
Finally, the constant term is any term without a variable.
6x−1 | 2+x | -2x+3−9y | |
---|---|---|---|
Term(s) | 6x and -1 | 2 and x | -2x, 3, and -9y |
x-term | 6x | x | -2x |
y-term | - | - | -9y |
Linear Term(s) | 6x | x | -2x and -9y |
Coefficient(s) | 6 | 1 | -2 and -9 |
Constant Term | -1 | 2 | 3 |
Select the required parts of the given linear expressions.
Ramsha is on the second day of a hiking excursion at math camp. On the first day, she hiked from base camp to the first station.
Note that 1.5x+10 represents a distance and the units of each term are miles. However, the units of x are hours. This gives a clue of the units of the coefficient 1.5.
In order to get rid of hours
and end up with miles,
the units of the coefficient must be miles per hour.
Therefore, the coefficient represents speed, or more precisely, the speed at which Ramsha walks.
In the previous example, an expression modeling a real-life scenario was provided. However, most of the time such expressions are not provided and must instead be created. The use of inductive reasoning can help with this process.
n | Number of Cubes | |
---|---|---|
Figure 1 | 0 | 1+3⋅0=1 |
Figure 2 | 1 | 1+3⋅1=4 |
Figure 3 | 2 | 1+3⋅2=7 |
Figure 4 | 3 | 1+3⋅3=10 |
Figure 121 | 120 | 1+3⋅120=361 |
At the end of the math camp, the students all visit an amusement park. Tiffaniqua did so well at camp that she won a coupon that allows her entire friend group to go on rides for x dollars per ride. By the end of the day, the group has gone on 11 rides and each person has eaten one hot dog.
The total amount of money paid is the sum of the amount paid for the 11 rides and the amount spent in hot dogs. The cost per person is the total cost divided by the number of people.
In the previous two examples, each situation was represented by an algebraic expression. There are some cases where writing an expression is not enough to model a situation. In such cases, an equation might be required.
Equations always contain an equals sign, while expressions do not. In fact, an equation can be seen like a statement that connects two expressions with an equals sign.
When learning about equations, a good first step is to start with linear equations, which involve only one variable.
A linear equation is an equation with at least one linear term and any number of constants. No other types of terms may be included. Linear equations in one variable have the following form, where a and b are real numbers and a=0.
Zosia's savings can be modeled by a linear expression of the form at+b, where a and b are real numbers.
0.5t+15=25
What is the coefficient for the x-term in this situation?
Notice how the number of people sat increases with each table added.
Begin by making sense of the situation. At least 1 table is needed for the family dinner. In this case, 4 people can be seated.
For each subsequent table, two more people are seated.
Kriz has $1000 saved. They need a total of $2000 to buy a new gaming laptop.
To start writing an equation, we need to put the equality sign in the middle. ... = ... Kriz saves $50 each week, so we can find their new savings by multiplying 50 by the number of weeks passed since they started saving money. Let's put this on the left-hand side of the equation! 50w = ... This money will be used for their new laptop. Since Kriz started with $1000, we can find the total amount of money saved by adding these amounts. 1000+50w = ... Since Kriz aims to buy a $2000 gaming laptop, we will finish our equation by setting this expression equal to 2000. 1000+50w=2000
LaShay is making cookies for her cousins. She bakes the cookies in small batches of 5.
To start writing an equation, we need to put the equality sign in the middle. ... = ... LaShay bakes 5 cookies in each batch, so we multiply 5 by the number of batches b she made. Let's put this on the right-hand side of the equation! ... = 5b These cookies will be given to LaShay's cousins, but not before she eats two of them. This means that we will subtract 2 from the total amount of cookies LaShay baked. ... = 5b-2 Finally, we write the total amount of cookies to be given to her cousins on the left-hand side of the equation. T=5b-2
Magdalena wants to play 2 games of golf this weekend.
To start writing an equation, we need to put the equality sign in the middle. ... = ... We know from the exercise that a single pack of golf balls contains 4 balls. This means that if Magdalena buys p packs, she will have 4 p golf balls. Let's write that on the right-hand side of the equality. ... = 4 p This value should be equal to the number of golf balls Magdalena wants for each game, 20, multiplied by the number of games she will play, 2. 20* 2=4p This can be simplified by performing the multiplication on the left-hand side of the equation. 40=4p