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| 14 Theory slides |
| 10 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Topics Related to Transformations of Functions
Topics Related to Trigonometric Functions
Like other functions, the parent functions of sine, cosine, and tangent can be transformed. The graphs of y=asin (bx), y=acos (bx), and y=atan (bx) represent stretch or shrink transformations of their parent functions.
The graph of a parent trigonometric function can be vertically stretched or shrunk by multiplying the function rule by a constant, positive number a. If a>1, the function will be stretched. Conversely, the function will be shrunk if 0< a<1.
factor a changes.The graph of a trigonometric function can be horizontally stretched or shrunk by multiplying the input of the function by a positive number b. If b>1, the graph shrinks horizontally by a factor of b. Conversely, if 0< b<1, the graph stretch horizontally by a factor of b.
Horizontal Stretch or Shrink | ||
---|---|---|
Parent Function | 0 | b>1 |
y=sin x | y=sin ( bx) Stretch parent function horizontally by a factor of b |
y=sin ( bx) Shrink parent function horizontally by a factor of b |
y=cos x | y=cos ( bx) Stretch parent function horizontally by a factor of b |
y=cos ( bx) Shrink parent function horizontally by a factor of b |
y=tan x | y=tan ( bx) Stretch parent function horizontally by a factor of b |
y=tan ( bx) Shrink parent function horizontally by a factor of b |
Graph:
b= 0.16
|0.16|=0.16
Use a calculator
Round to 1 decimal place(s)
y= sin x ⇒ h= 20 sin ( 0.16t) Note that the variables need to be changed from (x,y) to (t,h). The axis names of the coordinate plane also need to be changed. Consider the table to review what the values of a and b represent.
Transformations of h=sin t to h=a sin (bt) | |
---|---|
Vertical Stretch or Shrink | If a>1, h= sin t stretches vertically by a h= a sin t |
If 0< a< 1, h= sin t shrinks vertically by a h= a sin t | |
Horizontal Stretch or Shrink | If b>1, h= sin t shrinks horizontally by b h=sin ( bt) |
If 0< b< 1, h= sin t stretches horizontally by b h=sin ( bt) |
After going on the Ferris wheel, Dominika and Paulina go up to the big red triangular tower to see the townscape from the viewing deck.
Paulina wonders how to find the height of the tower. Dominika says that the height y, in meters, of a tower like this one can be modeled by the following tangent function, where θ is the angle indicated. y=10 tan (1.5θ)
Period: 2π3
y= atan( b θ) ⇓ y= 10 tan ( 1.5θ) Remember that a tangent function has no amplitude because it has no maximum and minimum values. Now recall the formulas for the period and asymptotes of a tangent function.
y=a tan(b θ) | |
---|---|
Period | π/|b| |
Asymptotes | π/2|b| |
Next, substitute b=1.5 into the corresponding formulas to identify the period and asymptotes. Period:& π/|1.5| ⇒ 2π/3 [0.8em] Asymptote:& π/2|1.5| ⇒ π/3 The period of the function is 2π3. Recall that the period is the distance between any two consecutive vertical asymptotes. Since there is no translation, the branch that passes through the origin has one asymptotes at π3 and the other at 2π3 units in the negative direction. Second Asymptote: π/3-2π/3=-π/3 The second asymptote of this branch is located at - π3. The next asymptotes can be found by moving 2π3 units to the left or right. Positive Asymptotes:& +2π/3 ⇒ π, 5π/3, 7π/3... [0.8em] Negative Asymptotes:& -2π/3 ⇒ -π, -5π/3, -7π/3... In other words, the asymptotes can be located at the odd multiples of π3.
Transformations of y=tan θ to y=a tan (b θ) | |
---|---|
Vertical Stretch or Shrink | If a>1, y= tan θ stretches vertically by a y= a tan θ |
If 0< a< 1, y= tan θ shrinks vertically by a y= a tan θ | |
Horizontal Stretch or Shrink | If b>1, y= tan θ shrinks horizontally by b y=tan ( bθ) |
If 0< b< 1, h= sin θ stretches horizontally by b h=sin ( bθ) |
θ= 50 ^(∘)
Multiply
Use a calculator
Round to 2 decimal place(s)
Trigonometric functions can be translated vertically or horizontally like the other functions. Next, these translations will be examined one at a time.
Let f(x) be a parent trigonometric function. Then, f(x)+k will translate the parent function vertically. If k>0, then the graph moves k units up. However, if k<0, then the graph moves k units down.
Vertical Translations | ||
---|---|---|
Parent Function | k>0 | k<0 |
y=sin x | y=sin x+ k, Translation k units up |
y=sin x -k, Translation k units down |
y=cos x | y=cos x+ k, Translation k units up |
y=cos x -k, Translation k units down |
y=tan x | y=tan x+ k, Translation k units up |
y=tan x -k, Translation k units down |
A horizontal translation of a periodic function is called a phase shift. The graph of f(x−h) represents a horizontal translation of f(x) by h units. For example, consider the parent functions of sine, cosine, and tangent functions. If h>0, the parent trigonometric function will be shifted to the right h units, while if h<0, the function will be shifted to the right h units.
Horizontal Translations | ||
---|---|---|
Parent Function | h>0 | h<0 |
y=sin x | y=sin (x- h) Translation h units to the right |
y=sin (x +h) Translation h units to the left |
y=cos x | y=cos (x- h) Translation h units to the right |
y=cos (x +h) Translation h units to the left |
y=tan x | y=tan (x- h) Translation h units to the right |
y=tan (x +h) Translation h units to the left |
Now Dominika and Paulina are waiting to ride the carousel in the amusement park. The girls enjoy the up and down movement of wooden horses.
Paulina thinks that the movement of a rider on a horse looks like a cosine function. While talking to the operator of the ride, the girls learn that each horse has a special route. They choose horses whose routes can be represented by the following functions. Dominika: & y= cos x Paulina: & y= cos (x+π)-1
Amplitude: |a| [0.5em] Period: 2π/|b| Using this information, rewrite the given functions to identify the values of a and b.
Write in the Form y=a cos b(x-h)+k | Amplitude: |a| | Period: 2π/|b| | |
---|---|---|---|
y= cos x | y= 1 cos 1(x- 0)+ 0 | | 1|= 1 | 2π/| 1|=2 π |
y=cos(x+π)-1 | y= 1 cos 1(x-( -π))+( -1) | | 1|= 1 | 2π/| 1|=2 π |
y=acosb(x-h)+k ⇓ y= 1 cos 1(x-( -π))+( -1) Note that h= -π and k= -1. Because h<0, the parent function has been translated π units to the left. Next, since k<0, the graph has been translated 1 unit down.
After riding on the carousel, Dominika and Paulina are looking for something more exciting when they hear the screams coming from the roller coaster. They watch the roller coaster for a while, then see the section where people are most excited and scream the loudest.
The track in this section is quite steep. The girls do some quick math and determine that the path of the roller coaster can be modeled by the following tangent function. y=tan (x-3π)+1
y= a tan b(x- h)+ k ⇓ y= 1 tan 1(x- 3π)+ 1 Now recall the formulas for the period and asymptotes of a tangent function. Period: & π/| b| [0.8em] Asymptote:& π/|2 b| Since b= 1, substitute this value into the formulas. Period: π/| 1| =π [0.8em] Asymptote: π/|2( 1)|=π/2 The period of the given tangent function is π and its asymptotes are at the odd multiples of π2.
y= a tan b(x- h)+ k ⇓ y= 1 tan 1(x- 3π)+ 1 Here, h= 3π and k= 1 represent the horizontal and vertical translations, respectively. Consider the following table to review how these values translate the parent tangent function.
Translations of y=tan θ to y= tan (θ -h)+k | |
---|---|
Vertical Translation | If k>0, y=tan θ moves $ k$ units up y= tan (x)+ k |
If k<0, y=tan θ moves $ k$ units down y= tan (x) -k | |
Horizontal Translation | If h>0, y=tan θ moves $ h$ units to the right y= tan (x- h) |
If h<0, y=tan θ moves $ h$ units to the left y= tan (x + h) |
From the table, it can be concluded that the function y=tan (x- 3π)+ 1 results from shifting the parent tangent function 3π units to the right and 1 unit up.
After the roller coaster, Dominika and Paulina decided to take a rest. They see a math game where each winner is awarded a teddy bear and think that it may be fun to take a look at the question.
Identify the parent function and apply one transformation at a time.
To find the correct function rule to win the game, start by recalling the general form of a transformed sine function. y= a sin b(x- h)+ k Now, recall what the variables a, b, h, and k represent.
Transformations of y=sin x | |
---|---|
Vertical Stretch or Shrink | y= a sin x If a>1, y= sin x stretches vertically by a |
y= a sin x If 0< a< 1, y= sin x shrinks vertically by a | |
Horizontal Stretch or Shrink | y=sin ( bx) If b>1 y= sin x shrinks horizontally by b |
y=sin ( bx) If 0< b< 1 y= sin x stretches horizontally by b | |
Vertical Translation | y= sin (x)+ k If k>0, y= sin x moves $ k$ units up |
y= sin (x)+ k If k<0, y= sin x moves $ k$ units down y= sin (x) -k | |
Horizontal Translation | y= sin (x- h) If h>0, y= sin x moves $ h$ units to the right |
y= sin (x- h) If h<0, y= sin x moves $ h$ units to the left |
Substitute values
a-(- b)=a+b
Dominika and Paulina have had fun during the day in the amusement park. They decide to come again together next week. To choose an appropriate day, they check the weather for the next two weeks.
The sine function can now be written by using all of this information. Start by recalling the general transformed form of a sine function. y= a sin b(x- h)+ k In this form, |a| is the amplitude. According to graph, the amplitude is 25. |a|=25 ⇓ a=25 or a=- 25 To determine the sign of a, compare its graph with the graph of parent sine function.
p= 14
LHS * |b|=RHS* |b|
.LHS /14.=.RHS /14.
|b|=b
a/b=.a /2./.b /2.
Transformations of y=sin x | |
---|---|
Vertical Stretch or Shrink | y= a sin x If a>1, y= sin x stretches vertically by a |
y= a sin x If 0< a< 1, y= sin x shrinks vertically by a | |
Horizontal Stretch or Shrink | y=sin ( bx) If b>1, y= sin x shrinks horizontally by b |
y=sin ( bx) If 0< b< 1, y= sin x stretches horizontally by b | |
Vertical Translation | y= sin (x)+ k If k>0, y= sin x moves $ k$ units up |
y= sin (x) -k If k<0, y= sin x moves $ k$ units down | |
Horizontal Translation | y= sin (x- h) If h>0, y= sin x moves $ h$ units to the right |
y= sin (x+ h) If h<0, y= sin x moves $ h$ units to the left | |
Reflection | y= - a sin x If a<0, y= sin x reflects in the midline y= k |
Now recall the function rule written in Part A again. y= -25 sin π/7x+ 70 According to the table, it can be said that the function rule represents a vertical stretch by a factor of 25, a horizontal stretch by a factor of π7, and a vertical translation of parent sine function 70 units up. Also, since a= -25 is less than 0, there is a reflection in the midline y= 70.
Parent Function | Transformed Form of the Function |
---|---|
y=cot x | y= a cot b(x- h)+ k |
y=sec x | y= a sec b(x- h)+ k |
y=csc x | y= a csc b(x- h)+ k |
Which of the following is the graph of the parent sine function with a vertical stretch by a factor of 4 and a horizontal shrink by a factor of 2?
We will start by drawing the graph of a parent sine function. Let's first find its period and amplitude. To do so, we need to rewrite it in the form y= 1 sin ( 1x) to apply the following formulas. Period: & 2π/| b| ⇒ 2π/| 1|=2π [0.5em] Amplitude: & | a| ⇒ | 1|=1 Since sin(0)=0, its graph will pass through the origin. By knowing these information, we can now draw its graph.
We will start by stretching the parent sine function vertically by a factor of 4. In other words, we will multiply its amplitude by 4. Since the amplitude of the parent sine function is 1, we will stretch its amplitude to 4.
Then we will stretch the sine function horizontally by a factor of 2. To do so, we will divide the length of one cycle, which is 2π, by 2. By doing this, the period of the horizontally stretched function will be π.
The transformed sine function matches with option B.
We want to identify the types of the transformations applied to the parent cosine function. y= cos x ⇒ y= 2/5 cos ( 3x) Notice that the given function is in the form y= a cos( bx). With this in mind, we will now consider the following table to review what the values of a and b represent.
Transformations of y=cos x to y=a cos (bx) | |
---|---|
Vertical Stretch or Shrink | If a>1, y= cos x stretches vertically by a y= a cos x |
If 0< a< 1, y= cos x shrinks vertically by a y= a cos x | |
Horizontal Stretch or Shrink | If b>1, y= cos x shrinks horizontally by b y=cos ( bx) |
If 0< b< 1, y= cos x stretches horizontally by b y=cos ( bx) |
In the given function rule, the value of a is less than 1, which represents a vertical shrink by a factor of 25. The value of b is greater than 1, which represents a horizontal shrink by a factor of 3.
Which of the following is the graph of a parent cosine function translated π units to the left and 1 unit up?
We will start by drawing the graph of a parent cosine function. Let's first find its period and amplitude. To do so, we need to rewrite it in the form y= 1 cos ( 1x) to apply the following formulas. Period: & 2π/| b| ⇒ 2π/| 1|=2π [0.5em] Amplitude: & | a| ⇒ | 1|=1 Since cos(0)=1, the y-intercept of the function will be at (0,1). By knowing these information, we can now draw its graph.
Now, we will translate this graph π units to the left.
Then, we will translate the obtained graph 1 unit up.
Comparing our graph with the given options, we can see that the translated cosine function graph matches with option C.
We want to identify the types of the translations applied to the parent tangent function. y= tan x ⇒ y=tan(x- 2π)+( -4) Notice that the given function is in the form y=tan(x- h)+( k), where h= 2π and k= -4. With this in mind, we will now consider the following table to review what the values of h and k represent.
Translations of y=tan x to y= tan (x -h)+k | |
---|---|
Vertical Translation | If k>0, y=tan x moves $ k$ units up y= tan (x)+ k |
If k<0, y=tan x moves $ k$ units down y= tan (x) -k | |
Horizontal Translation | If h>0, y=tan x moves $ h$ units to the right y= tan (x- h) |
If h<0, y=tan x moves $ h$ units to the left y= tan (x + h) |
In the given function rule, the value of h is greater than 0, which represents a horizontal translation 2π units to the right. The value of k is less than 0, which represents a vertical translation 4 units down.
Consider the following sine function. y=3 sin x -1
Which of the given graphs is a reflection of the given sine function's graph in the x-axis?
Which of the given graphs is a reflection of the given sine function's graph in the y-axis?
We will start by drawing the given sine function. To do so, we will write it in the general form of a transformed sine function. y= 3 sin 1(x- 0) +( -1) ⇕ y= a sin b(x- h) +( k) In this form, a represents a vertical stretch or a shrink, b represents a horizontal stretch or shrink, h represents a phase shift, and k represents a vertical translation. Let's now identify these variables for our function.
Variable | Transformation |
---|---|
a=3 | Since 3>0, it represents a vertical stretch of the parent sine function by a factor of 3 |
b=1 | Since b=1, there is no horizontal stretch or shrink. |
h=0 | Since h=0, there is no phase shift. |
k=-1 | Since k<0, it represents a vertical translation of the parent sine function 1 unit down |
To apply the transformations mentioned in the above table, we will first recall the graph of the parent sine function.
Now, we will stretch it vertically by a factor of 3. Since the amplitude of the parent sine function is 1, it will be 3 when we stretch it by a factor of 3.
Then, we will translate the stretched sine function 1 unit down.
Finally, we will reflect the graph of the given sine function across the x-axis.
The reflected graph matches option D.
This time we will reflect the graph of the given sine function across the y-axis. Remember that we have already drawn the original graph in Part A. Let's now reflect it across the y-axis!
The reflected graph matches option B.
Consider the following cosine function. y=2 cos (x-5π)-4
We are asked to find the equation of a function whose graph is a reflection of the graph of the given cosine function in the x-axis. To do so, we will multiply the function rule by -1. Function Rule y=2cos (x-5π)-4 ⇓ Reflection in thex -axis y= - (2 cos (x-5π)-4) Let's distribute -1 into the parentheses and simplify the right hand side of the equation.
This time we will write the equation of a function whose graph is a reflection of the given cosine function's graph in the y-axis. To do so, we will only multiply the input by -1. Notice that the x-variable represents the the input of the given function.
Function Rule
y=2cos (x-5π)-4
⇓
Reflection in they -axis
y=2 cos ( - x-5π)-4