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| 14 Theory slides |
| 10 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Topics Related to Transformations of Functions
Topics Related to Trigonometric Functions
Like other functions, the parent functions of sine, cosine, and tangent can be transformed. The graphs of y=asin(bx), y=acos(bx), and y=atan(bx) represent stretch or shrink transformations of their parent functions.
The graph of a parent trigonometric function can be vertically stretched or shrunk by multiplying the function rule by a constant, positive number a. If a>1, the function will be stretched. Conversely, the function will be shrunk if 0<a<1.
Vertical Stretch or Shrink | ||
---|---|---|
Parent Function | a>1 | 0<a<1 |
y=sinx | y=asinx Stretch parent function vertically by a factor of a |
y=asinx Shrink parent function vertically by a factor of a |
y=cosx | y=acosx Stretch parent function vertically by a factor of a |
y=acosx Shrink parent function vertically by a factor of a |
y=tanx | y=atanx Stretch parent function vertically by a factor of a |
y=atanx Shrink parent function vertically by a factor of a |
The graph of a trigonometric function can be horizontally stretched or shrunk by multiplying the input of the function by a positive number b. If b>1, the graph shrinks horizontally by a factor of b. Conversely, if 0<b<1, the graph stretch horizontally by a factor of b.
Horizontal Stretch or Shrink | ||
---|---|---|
Parent Function | 0<b<1 | b>1 |
y=sinx | y=sin(bx) Stretch parent function horizontally by a factor of b |
y=sin(bx) Shrink parent function horizontally by a factor of b |
y=cosx | y=cos(bx) Stretch parent function horizontally by a factor of b |
y=cos(bx) Shrink parent function horizontally by a factor of b |
y=tanx | y=tan(bx) Stretch parent function horizontally by a factor of b |
y=tan(bx) Shrink parent function horizontally by a factor of b |
Graph:
b=0.16
∣0.16∣=0.16
Use a calculator
Round to 1 decimal place(s)
Transformations of h=sint to h=asin(bt) | |
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Vertical Stretch or Shrink | If a>1,h=sint stretches vertically by ah=asint
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If 0<a<1,h=sint shrinks vertically by ah=asint
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Horizontal Stretch or Shrink | If b>1,h=sint shrinks horizontally by bh=sin(bt)
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If 0<b<1,h=sint stretches horizontally by bh=sin(bt)
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After going on the Ferris wheel, Dominika and Paulina go up to the big red triangular tower to see the townscape from the viewing deck.
Period: 32π
y=atan(bθ) | |
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Period | ∣b∣π |
Asymptotes | 2∣b∣π |
Transformations of y=tanθ to y=atan(bθ) | |
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Vertical Stretch or Shrink | If a>1,y=tanθ stretches vertically by ay=atanθ
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If 0<a<1,y=tanθ shrinks vertically by ay=atanθ
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Horizontal Stretch or Shrink | If b>1,y=tanθ shrinks horizontally by by=tan(bθ)
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If 0<b<1,h=sinθ stretches horizontally by bh=sin(bθ)
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θ=50∘
Multiply
Use a calculator
Round to 2 decimal place(s)
Trigonometric functions can be translated vertically or horizontally like the other functions. Next, these translations will be examined one at a time.
Let f(x) be a parent trigonometric function. Then, f(x)+k will translate the parent function vertically. If k>0, then the graph moves k units up. However, if k<0, then the graph moves k units down.
Vertical Translations | ||
---|---|---|
Parent Function | k>0 | k<0 |
y=sinx | y=sinx+k, Translation k units up |
y=sinx−k, Translation k units down |
y=cosx | y=cosx+k, Translation k units up |
y=cosx−k, Translation k units down |
y=tanx | y=tanx+k, Translation k units up |
y=tanx−k, Translation k units down |
A horizontal translation of a periodic function is called a phase shift. The graph of f(x−h) represents a horizontal translation of f(x) by h units. For example, consider the parent functions of sine, cosine, and tangent functions. If h>0, the parent trigonometric function will be shifted to the right h units, while if h<0, the function will be shifted to the right h units.
Horizontal Translations | ||
---|---|---|
Parent Function | h>0 | h<0 |
y=sinx | y=sin(x−h) Translation h units to the right |
y=sin(x+h) Translation h units to the left |
y=cosx | y=cos(x−h) Translation h units to the right |
y=cos(x+h) Translation h units to the left |
y=tanx | y=tan(x−h) Translation h units to the right |
y=tan(x+h) Translation h units to the left |
Now Dominika and Paulina are waiting to ride the carousel in the amusement park. The girls enjoy the up and down movement of wooden horses.
Write in the Form y=acosb(x−h)+k | Amplitude: ∣a∣ | Period: ∣b∣2π | |
---|---|---|---|
y=cosx | y=1cos1(x−0)+0 | ∣1∣=1 | ∣1∣2π=2π |
y=cos(x+π)−1 | y=1cos1(x−(-π))+(-1) | ∣1∣=1 | ∣1∣2π=2π |
After riding on the carousel, Dominika and Paulina are looking for something more exciting when they hear the screams coming from the roller coaster. They watch the roller coaster for a while, then see the section where people are most excited and scream the loudest.
Translations of y=tanθ to y=tan(θ−h)+k | |
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Vertical Translation | If k>0,y=tanθ moves k units upy=tan(x)+k
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If k<0,y=tanθ moves k units downy=tan(x)−k
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Horizontal Translation | If h>0,y=tanθ moves h units to the righty=tan(x−h)
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If h<0,y=tanθ moves h units to the lefty=tan(x+h)
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From the table, it can be concluded that the function y=tan(x−3π)+1 results from shifting the parent tangent function 3π units to the right and 1 unit up.
After the roller coaster, Dominika and Paulina decided to take a rest. They see a math game where each winner is awarded a teddy bear and think that it may be fun to take a look at the question.
Identify the parent function and apply one transformation at a time.
Transformations of y=sinx | |
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Vertical Stretch or Shrink | y=asinxIf a>1,y=sinx stretches vertically by a
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y=asinxIf 0<a<1,y=sinx shrinks vertically by a
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Horizontal Stretch or Shrink | y=sin(bx)If b>1y=sinx shrinks horizontally by b
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y=sin(bx)If 0<b<1y=sinx stretches horizontally by b
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Vertical Translation | y=sin(x)+kIf k>0,y=sinx moves k units up
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y=sin(x)+kIf k<0,y=sinx moves k units downy=sin(x)−k
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Horizontal Translation | y=sin(x−h)If h>0,y=sinx moves h units to the right
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y=sin(x−h)If h<0,y=sinx moves h units to the left
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Substitute values
a−(-b)=a+b
Dominika and Paulina have had fun during the day in the amusement park. They decide to come again together next week. To choose an appropriate day, they check the weather for the next two weeks.
p=14
LHS⋅∣b∣=RHS⋅∣b∣
LHS/14=RHS/14
∣b∣=b
ba=b/2a/2
Transformations of y=sinx | |
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Vertical Stretch or Shrink | y=asinxIf a>1,y=sinx stretches vertically by a
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y=asinxIf 0<a<1,y=sinx shrinks vertically by a
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Horizontal Stretch or Shrink | y=sin(bx)If b>1,y=sinx shrinks horizontally by b
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y=sin(bx)If 0<b<1,y=sinx stretches horizontally by b
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Vertical Translation | y=sin(x)+kIf k>0,y=sinx moves k units up
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y=sin(x)−kIf k<0,y=sinx moves k units down
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Horizontal Translation | y=sin(x−h)If h>0,y=sinx moves h units to the right
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y=sin(x+h)If h<0,y=sinx moves h units to the left
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Reflection | y=-asinxIf a<0,y=sinx reflects in the midline y=k
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Parent Function | Transformed Form of the Function |
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y=cotx | y=acotb(x−h)+k |
y=secx | y=asecb(x−h)+k |
y=cscx | y=acscb(x−h)+k |
Which of the following graphs is the graph of the given cosine function?
We are given a function that models the blood pressure P of a person at rest at time t. P=120-15 cos 5π/2 t The blood pressure P is given in millimeters of mercury and t is time in seconds. We want to graph this function. We will start by comparing it with the general form of a transformed cosine function. General Form y= a cos b(t- h)+ k [0.5em] Given Function P= -15 cos 5π/2 (t- 0)+ 120 As we can see, a= - 15, b= 5π2, h= 0, and k= 120. Now let's recall how these variables affect the graph of the parent cosine function.
Transformations of y=cos x | |
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Vertical Stretch or Shrink | y= a cos x If a>1, y= cos x stretches vertically by a |
y= a cos x If 0< a< 1, y= cos x shrinks vertically by a | |
Horizontal Stretch or Shrink | y=cos ( bx) If b>1, y= cos x shrinks horizontally by b |
y=cos ( bx) If 0< b< 1, y= cos x stretches horizontally by b | |
Vertical Translation | y= cos (x)+ k If k>0, y= cos x moves $ k$ units up |
y= cos (x) -k If k<0, y= cos x moves $ k$ units down | |
Horizontal Translation | y= cos (x- h) If h>0, y= cos x moves $ h$ units to the right |
y= cos (x+ h) If h<0, y= cos x moves $ h$ units to the left | |
Reflection | y= - a cos x If a<0, y= cos x reflects in the midline y= k |
Now we will transform the parent cosine function step by step. First, we will stretch the parent cosine function vertically by a factor of 15 and shrink it horizontally by a factor of 5π2, or 2.5 π. Let's calculate the amplitude and period of the cosine function. Amplitude: & | a| ⇒ | 15|=15 [0..5em] Period: & 2π/| b| ⇒ 2π/| 2.5 π| =0.8 Now we will draw the transformed function by using the amplitude and period that we found.
Great! Notice that a= - 15. Since it is less than 0, it also represents a reflection in the x-axis or across the midline y=0. Let's now reflect our graph in the x-axis!
We will next translate this function 120 units up. Since h= 0, there is no phase shift.
Finally, we will set the starting point of the graph at t=0 to find the desired graph because the time cannot be negative.
The graph matches option C.
We know that one cycle represents one heartbeat. To find the number of heartbeats per minute, we will examine the graph. From the graph we can tell that one cycle takes 0.8 seconds.
We want to determine the pulse rate of the person in heartbeats per minute. Because there are 60 seconds in 1 minute, we need to find the number of heartbeats in 60 seconds. Since one heartbeat takes 0.8 seconds, let's divide 60 by 0.8. 60/0.8=75 There are 75 heartbeats in 60 seconds. This means that the pulse rate is 75 heartbeats per minute.
Consider the following graph of the function y=5cos2x.
Which of the following graphs is the graph of the function f(x)=5sec2x? Use the given graph to determine the correct option.
We are asked to use the given graph of the cosine function y=5cos 2x to graph the cosecant function f(x)= 5sec 2x. Notice that these functions are reciprocal functions. 5 sec (2x)=1/5 cos (2x) This means that the asymptotes of f(x)=5sec 2x occur when 5cos 2x=0. In other words, we can draw these asymptotes at the points where the graph of y=5cos 2x intersects the x-axis.
Now, we will find the period of f(x)= 5sec 2x. Note that the period of f(x)=5sec 2x and the period of y= 5cos 2x are the same because they are reciprocals. Since our function is in the form y= a cos b, we can substitute b= 2 in the following formula to find its period. Period: 2π/| b| = 2π/| 2| ⇒ π The graph of y=5cos 2 x has a period of π.
The period of the graph of f(x)=5sec 2x will also be π. Now we will plot the points to show the local minimums and maximums of y, which also belong to the graph of f. The secant function's graph will increase when the cosine function's graph decreases and the secant function's graph will decrease when the cosine function's graph increases around these points.
To graph the left portion of the function, we come down from the left asymptote, pass through the point, and move up towards the right asymptote. Then for the right portion of the graph, we will follow similar steps and come up from the left asymptote, pass through the point, and move towards the right asymptote.
This graph matches option C.
We will determine whether it is possible to write a secant function that has the same graph as y=csc x. To do so, let's first recall what we know about the secant function. Below we have the graph of the function.
We know that y=sec x is a reciprocal function of y=cos x. Similarly, the cosecant function y=csc x is a reciprocal of the sine function y=sin x.
Function | Reciprocal |
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y=sin x | y=csc x |
y=cos x | y=sec x |
Notice that the graph of y=cos x can be translated π2 units to the right to create the same graph as y=sin x.
This means that the graph of y=sec x can be translated π2 units to the right to create the same graph as y=csc x.
By doing this, we can write the cosecant function as a horizontal translation of the secant function. csc x= sec (x - π/2) Therefore, Tadeo is not correct. Notice that this is just one possible solution. We can actually write several types of translations between secant and cosecant functions that result in the same graph.