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1. The Basics of Event Probability
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Chapter 6
1. 

The Basics of Event Probability

This lesson delves into the basics of event probability, offering insights into sample space, favorable outcomes, and experimental probability. It aims to introduce these concepts in a manner that connects them to real-life situations. For instance, if one is participating in a game show and have to pick a door with a prize behind it, understanding sample space and favorable outcomes can increase your chances of winning. Similarly, experimental probability is discussed in the context of rolling dice or drawing marbles from a bag. This knowledge is not just theoretical; it has practical applications in various fields like statistics, game theory, and even in everyday decision-making.
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Lesson Settings & Tools
13 Theory slides
14 Exercises - Grade E - A
Each lesson is meant to take 1-2 classroom sessions
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The Basics of Event Probability
Slide of 13
In this lesson, some basics concepts of probability will be introduced and connected to real-life situations.

Catch-Up and Review

Here are a few recommended readings before getting started with this lesson.

Explore

Possible Outcomes of Target Shooting

Magdalena is in a target shooting competition. For her next test, the target has three zones and she can shoot three arrows.
A target Shooting and a bow and arrow
Assuming that Magdalena always hit the target, list all the possible results that Magdalena can get on the test.
Challenge

Probability of Winning a Prize

On a late-night game show, there are three closed doors. Behind one of the doors is a car, and there are sheep behind the other two. The host invites Tearrik to win the car by choosing only one door.
Applet to pick a door out of three to try winning the car
a What are the chances that Tearrik will choose the winning door? Round the answer to two decimal places.
b What are the chances of choosing a door with a sheep? Round the answer to two decimal places.
Discussion

Defining Experiments in Probability

Below, some basic definitions of probability are examined.

Concept

Experiment - Probability

An experiment is a process used to determine the probability of an event occurring in the future. In finding probability, an experiment is an action that can be repeated infinitely many times and has a variety of results called outcomes. Even rolling a die can be considered an experiment.
Applet that allows to roll a die
Experiments are repeated several times to collect data, and each repetition is called a trial. For example, if a die is thrown times, each throw is considered a trial. An experiment is usually performed to estimate the theoretical probability of a particular outcome.
Concept

Outcome

An outcome is a possible result of a probability experiment. For example, when rolling a six-sided die, getting a is one possible outcome.

A die with 3 on the top face, 1 on the front face, and 2 on the right face.
Note that when performing an experiment, each possible outcome is unique. That means only one outcome will occur for each trial.
Concept

Event

An event is a combination of one or more specific outcomes. For example, when playing cards, an event might be drawing a spade or a heart. For this event, one possible outcome is drawing the or drawing the

A deck of cards, a 7 of hearts, and the ace of spades

However, these are not the only outcomes of this event. All the possible outcomes that satisfy the event are listed below.

Concept

Sample Space

The sample space of an experiment is the set of all possible outcomes. For example, when flipping a coin, there are two possible outcomes: heads, H, or tails, T. Therefore, the sample space is

Coin flip outcomes: Head and Tail in the sample space.

Here, the sample space is shown in a tree diagram. Each row represents the possible outcomes of a toss. When the coin is flipped another time, the tree diagram gets another row with the possible outcomes.

sample space of flipping a coin twice

In this case, the sample space has possible outcomes.

Example

Sample Space of Rolling Dice

For each of the following experiments, list the possible outcomes in the sample space and count the total number of outcomes.

a Roll one die.
A red die
b Roll two dice at the same time.
Two six-sided dice are placed adjacent to each other.

Answer
a Number of Outcomes:

Outcomes:
b Number of Outcomes:

Outcomes:

Outcomes for rolling two dice

Hint
a What are the possible outcomes when a die is rolled?
b For each outcome of the first die, there are six different outcomes for the second die.

Solution
a When a die is rolled, there are different possible outcomes.
A die and its 6 outcomes

Consequently, the sample space is the set

b As was found in Part A, each possible outcome of rolling one die is just one number. However, when rolling two dice, one possible outcome is getting a on the first die and a on the second die.
Therefore, each outcome in the sample space will consist of two numbers — one for each die.
A two-elements set where the first element comes from Die 1 and the second element comes from die 2

To list all the possible outcomes, create all possible combinations by determining one outcome for the first die and then varying the outcome of the second die. Then, change the outcome of the first die and repeat the process.

Outcomes for rolling two dice

Since each die has possible outcomes, the total number of possible outcomes for this experiment is

Example

Sample Space: Drawing Marbles From a Bag

Paulina bought two white and three black marbles, all of different sizes, and put them in a bag. When she got home, her little brother Diego and sister Emily asked her to give them two marbles. Paulina agreed but told them to draw one marble each without looking inside the bag. Diego drew the first marble, then Emily.

A bag, 2 white marbles, and 3 black marbles
a Assuming all the marbles are distinguishable, write down the sample space for the event of Diego and Emily randomly drawing two marbles from the bag. What is the total number of outcomes?
b How many of the outcomes in the sample space represent the case where Diego and Emily both drew white marbles?
c How many of the outcomes in the sample space represent the case where Diego and Emily both drew black marbles?
d How many of the outcomes in the sample space represent the case where Diego and Emily drew marbles of different colors?
e In a few words, write a different event for the situation presented.

Answer
a Number of Outcomes:

Outcomes:
Here, and represent the white marbles, and and represent the black marbles.
b Number of Outcomes:

Outcomes: and

c Number of Outcomes:

Outcomes:
d Number of Outcomes:

Outcomes:
e Example Event: Diego and Emily ask Paulina to give them two marbles each.

Hint
a Give each marble a label. How many outcomes does the first drawn marble have? How many outcomes does the second marble have?
b Look for the outcomes containing only the labels assigned to the white marbles.
c Look for the outcomes containing only the labels assigned to the black marbles.
d Look for the outcomes containing one label assigned to the white marbles and one label assigned to the black marbles.
e If Diego and Emily ask for a different number of marbles, this is a different event.

Solution
a Despite having only two colors, all five marbles are said to be distinguishable. That is why starting by labeling each of the marbles is a good option.
A bag, 2 white marbles, and 3 black marbles

Since both marbles are randomly drawn, each outcome of the event will consist of two labels. For the first marble, there are possible outcomes. For the second marble, there are possible outcomes because one marble has already been removed from the bag.

A two-element set where the first element comes from the first marble drawn and the second element comes from the second marble drawn
Since the Diego draws a marble first and Emily draws a marble after him, the order in which the marbles are drawn matters. Therefore, the outcomes and are different. The following table lists all the possible outcomes for the event of drawing two marbles from the bag.
Consequently, there are a total of possible outcomes in the sample space.
b The case in which two white marbles are drawn is represented by the outcomes containing only and From Part A, it can be seen that there are only two such outcomes — and
c The case in which two black marbles are drawn is represented by the outcomes containing neither nor Analyzing the sample space from Part A, six such outcomes can be found.
d The case in which one white and one black marble are drawn is represented by the outcomes containing one label and one label. From Part A, there are twelve such outcomes.
e There are an infinite number events that can be considered. For example, Diego and Emily could ask Paulina to give them two marbles each. In that case, the event would be the drawing of four marbles.
Discussion

Union, Intersection, and Complement of Events

Sometimes more than one event can be involved in an experiment. In such cases, it is important to know how to determine the union or intersection of the events.

Concept

Union - Probability

The union of two events and is the set of all the outcomes that are in or are in or in both and The union of and is usually written as or or
union of two events
The probability of the union of and is the probability that event or event will occur. It can be found using the Addition Rule of Probability.
Concept

Intersection - Probability

The intersection of two events and is the set of all the outcomes that satisfy both events and simultaneously. The intersection of and is usually written as or
Intersection of two Sets A and B
The probability of the intersection of and is the probability that and will occur and can be found using the Multiplication Rule of Probability.

Also, there may be situations where it is easier to determine which outcomes do not satisfy an event rather than determining which outcomes do. For such cases, the following concept will be useful.

Concept

Complementary Events

Complementary events are pairs of events where only one can occur at a time. The complement of an event is written as or It represents all possible outcomes that are not part of event For instance, when rolling a fair six-sided die, rolling an even number and rolling an odd number are complementary events.
A die and the even numbers highlighted
The union of an event and its complement is the entire sample space.
The probability of an event and its complement always adds up to
Example

Operating With Events

Let be the set of all integers from to
Sample Space U formed by the integers from 0 to 9
Consider the experiment of randomly picking a number from
  • Let be the event of picking a prime number.
  • Let be the event of picking an odd number.
  • Let be the event of picking a multiple of
a Write the complement of each event in words.
b List the outcomes of each event and its complement.
c Write the event in words and list its outcomes.
d Write the event in words and list its outcomes.
e Make a Venn diagram illustrating the set and the events and

Answer
a Complements:
  • is the event of picking a non-prime number.
  • is the event of picking an even number.
  • is the event of picking a number that is not a multiple of
b Outcomes of the Events:
Outcomes of the Complements:
c Intersection of Events: is the event of picking a prime, odd number.

Outcomes:

d Union of Events: is the event of picking either an odd number or a number that is not a multiple of

Outcomes:

e Venn Diagram:
Venn diagram with the three events A, B, and C

Hint
a To write the complement of an event, consider the opposite event.
b The complement of an event is the set of all the possible outcomes that are not in that event.
c Remember how the intersection of events is defined.
d Use the definition of a union of events.
e First, look for the numbers that are common for the three events. Then, look for the numbers that are in two events but not in the third one. Finally, look for the numbers from the sample space that do not occur in any of the events.

Solution
a By definition, the complement of an event is the set of all possible outcomes that are not in that event. Therefore, the complement of picking a prime number is picking a non-prime number. The complement of events and can be similarly written.
Event Complement
picking a prime number picking a non-prime number
picking an odd number picking an even number
picking a multiple of picking a number that is not a multiple of
b The outcomes of the event are all numbers in that are prime.
In a similar way, the outcomes of the remaining events can be written.
Finally, the outcomes of are the outcomes in that are not in Similarly for the outcomes of and
c By definition, the intersection of two events is the set of all outcomes that satisfy both events simultaneously. To write start by recalling what events and represent.

- event of picking a prime number
- event of picking an odd number

Therefore, is the event of picking a prime and odd number.

Number Is it prime? Is it odd?
No Yes
Yes No
Yes Yes
No No
Yes Yes
No No
Yes Yes
No No
No Yes

Consequently,

d By definition, the union of two events is the set of all outcomes that satisfy either of the events. Before writing what is, begin by remembering what each of these events represents.

- event of picking an odd number
- event of picking a number that is not a multiple of

Therefore, is the event of picking either an odd number or a number that is not multiple of

Number Is it odd? Is not a multiple of
Yes Yes
No Yes
Yes No
No Yes
Yes Yes
No No
Yes Yes
No Yes
Yes No

Consequently, Notice that is the only element of that is not in since it satisfies neither nor

e In order to make a Venn diagram, start by considering the sample space which is a set of integers from to
Sample Space U formed by the integers from 0 to 9

Next, draw three sets representing the events and and write down the outcomes of each event inside the corresponding set.

Diagram of the set U, and the sets A,B,C with the corresponding outputs inside

Comparing the outcomes of the three events, some conclusions can be drawn.

  • The number is common for the three events. Thus, the three sets intersect each other.
  • The numbers and are common for events and but they are not in
  • The number is common for events and but it is not in
  • The events and have nothing in common other than the number
  • The numbers and do not belong to any of the events.

With this information, the Venn diagram can be drawn.

Venn diagram with the three events A, B, and C
In the following diagram, the events and their complements can be appreciated separately.
Venn diagram with the three events A, B, and C and their complements
Discussion

Theoretical and Experimental Probability

Since an event is a combination of possible outcomes of an experiment, in some cases the event happens rarely, while in others it happens frequently. This frequency depends on the experiment and the event itself.

Concept

Probability

Probability measures the likelihood that something will occur. It can be any value from to or from to inclusive. When it is certain that the situation will not occur, the probability is Likewise, when it is certain that the situation will occur, the probability is
When probability is less than 0.5, the event is unlikely to happen, when probability is equal to 0.5, the event is equally likely to happen or not happen, when probability is greater than 0.5, the event is likely to happen.

The probability of an event occurring can be determined both theoretically and experimentally. Theoretical probability expresses the expected probability when all outcomes in a sample space are equally likely. In comparison, experimental probability is expressed by analyzing data collected from repeated trials of an experiment.

Concept

Theoretical Probability

When all outcomes in a sample space are equally likely to occur, the theoretical probability of an event is the ratio of the number of favorable outcomes to the number of possible outcomes.

Consider the roll of a standard six-sided die. There are six equally likely outcomes in the sample space. For the event of rolling an even number, there are three favorable outcomes. This can be called
A sample space of rolling a dice: {1,2,3,4,5,6}; the event A of rolling an even number consists of three outcomes {2,4,6}.
The probability of can be found by using the given ratio.
After simplification, it is obtained that is equal to Consequently, there is a chance an even number is rolled.

When an experiment is performed, the results may be a little different from what was expected. In other words, slightly different results may be obtained from what the theoretical probability predicted.

Concept

Experimental Probability

Experimental probability is the probability of an event occurring based on data collected from repeated trials of a probability experiment. For each trial, the outcome is noted. When all trials are performed, the experimental probability of an event is calculated by dividing the number of times the event occurs, or its frequency, by the number of trials.

By repeating an experiment many times, the result will trend toward the theoretical probability of the event. For example, consider the flip of a fair coin and the event that tails is the outcome. Use the applet to simulate the outcomes and calculate the experimental probability.
Flipping a Coin 100, 500, and 1000 times
The experimental probability of tails as an outcome is close to the theoretical probability of
Example

Theoretical Probability vs. Experimental Probability

Ramsha and Mark conducted an experiment consisting of rolling two dice and adding their results. The following diagram shows the numbers obtained in each roll.

The left column displays Ramsha's dice roll results, while the right column displays Mark's. The results are separated by a vertical line.

Consider the event of getting a result greater than or equal to

a What is the theoretical probability of this event? Round the answer to two decimal places.
b Find the experimental probability of the given event according to Ramsha's data. Round the answer to two decimal places.
c Find the experimental probability of the given event according to Mark's data. Round the answer to two decimal places.

Hint
a Determine all the possible outputs of rolling two dice. Then, calculate the sum of the outputs and count how many of them are greater than or equal to
b Start by finding the number of successes, the number of times the event was fulfilled.
c Divide the number of successes by the number of trials.

Solution
a To find the theoretical probability, the number of favorable outcomes should be divided by the total number of possible outcomes.
Since the experiment consists of rolling two dice and each die has possible outcomes, there is a total of possible combinations. Calculate the sum of the outputs for each combination.
Table with first row numbers from 1 to 6, first column numbers from 1 to 6

The in the second row and third column represents the event of rolling a on the first die and a on the second die. The other outcomes can be calculated in the same fashion. Next, highlight the outcomes satisfying the given event, that the sum of the dice is greater than or equal to

Highlighting the favorable outcomes
There is a total of favorable outcomes. With this information, the theoretical probability can be calculated.
▼
Substitute values and simplify
SubstituteII

,

ReduceFrac

CalcQuot

Calculate quotient

RoundDec

Round to decimal place(s)

Consequently, the probability of getting a sum greater than or equal to when two dice are rolled is about or Notice that the sample space of the experiment contains only outcomes.
However, the outcomes are not equally likely. From the above table, there is greater chance of rolling a than rolling a
b The experimental probability of an event equals the number of successes obtained divided by the number of trials.
Therefore, to find the experimental probability obtained by Ramsha, divide the number of successes she got by the number of trials she conducted. These two numbers can be deduced from the given diagram.
Favorable Outcomes obtained by Ramsha
As can be seen, Ramsha got successes in trials. With this information, the experimental probability can be found.
▼
Substitute values and simplify
SubstituteII

,

CalcQuot

Calculate quotient

RoundDec

Round to decimal place(s)

Consequently, for the given event, Ramsha got an experimental probability of or
c Similar to Part B, to find the experimental probability obtained by Mark, divide the number of successes he got by the number of trials he conducted. As before, this information can be found in the given diagram.
Favorable outcomes obtained by Mark
Mark got successes in trials. With this information, the experimental probability can be found.
▼
Substitute values and simplify
SubstituteII

,

ReduceFrac

CalcQuot

Calculate quotient

RoundDec

Round to decimal place(s)

Therefore, for the given event, Mark got an experimental probability of or
Discussion

Probability of the Complement of an Event

The probability of drawing a club from a standard deck of cards is Knowing this, what is the probability of drawing a spade, heart, or diamond if a card is drawn randomly?

Cards from the As to K

To figure it out, instead of counting the favorable outcomes, the complement rule can be used.

Rule

Complement Rule - Probability

The sum of the probability of an event and the probability of its complement is equal to

This formula is useful when calculating the probability of the complement of an event is easier than calculating the probability of the event itself. Then, the probability of the event is calculated as follows.

Proof

 Complement Rule
Let be an event, be its complement, and be the sample space. By the definition of the complement, the union of an event and its complement is equal to the entire sample space.
Because and represent the same event, their probabilities are equal.
Since the complement of consists of the outcomes that are not in events and are disjoint. By the Addition Rule of Probability, the probability of the union is the sum of the individual probabilities of each of the events.
Now the Transitive Property of Equality can be applied to the equalities.
Additionally, the probability of the entire sample space is equal to By applying the Transitive Property of Equality once more, the rule is proven.

Using the Subtraction Property of Equality, the formula for the probability of is obtained.

Applying this formula, the probability of drawing a spade, heart, or diamond can be computed.

Example

Counting Not Multiples of 5 vs. Counting Multiples of 5

Dylan cut out squares of paper and wrote a number from to on each square. He then put the papers in a bag and asked his dad to choose a paper at random.

Papers with the numbers from 1 to 100
What is the probability that Dylan's father picks a number that is not a multiple of

Hint

What is easier to count, the numbers that are not multiples of or the numbers that are multiples of Note that these sets of numbers are the complements of each other.

Solution
Start by remembering what the probability of an event is.
Let be the given event, picking a number that is not a multiple of However, counting the numbers from to that are not multiples of can be tedious. In this case, it is worth considering the complement of
Event Complement
Picking a number that is not a multiple of Picking a number that is a multiple of
Counting how many numbers are multiples of is an easier task.
There is a total of favorable outcomes for Knowing this, the probability of can be calculated.
The probability of picking a multiple of is Applying the Complement Rule, the probability of can be computed.
Substitute

SubTerms

Subtract terms

Consequently, the probability that Dylan's father picks a number that is not a multiple of is
Closure

Chances of Picking the Right Door

At the beginning of this lesson, Tearrik was invited by the host of a late-night game show to pick one door out of thee to win a car. However, behind two of the doors are sheep.
Applet to pick a door out of three to try winning the car
a What are the chances that Tearrik will choose the winning door? Round the answer to two decimal places.
b What are the chances of choosing a door with a sheep? Round the answer to two decimal places.
c If there were doors and prizes, what is the chance that Tearrik picks a door with a sheep behind it? Round the answer to two decimal places.

Hint
a Divide the number of favorable outcomes by the number of possible outcomes.
b Use the Complement Rule.
c How many of the doors have sheep behind them?

Solution
a The probability of an event is the quotient of the number of favorable outcomes to the number of possible outcomes.
Since there are three doors, there are total possible outcomes, of which only is favorable. Knowing this, the chance that Tearrik will choose the wining door can be calculated.
b Note that the event of picking a door with a sheep is the complement of picking the winning door. Therefore, the Complement Rule can be used.
In Part A, the probability of picking the winning door was found to be about Substituting this value into the previous equation, the probability of picking a door with a sheep will be obtained.
c In this case, there are doors and prizes. This time finding a sheep is the favorable outcome.
P = Number of favorable outcomes / Number of possible outcomes
Since there are prizes, there are doors with sheep. With this information, the required probability can be found.
SubstituteII

,

ReduceFrac

CalcQuot

Calculate quotient

RoundDec

Round to decimal place(s)



Level 1
Level 2
Level 3
The Basics of Event Probability
Exercises

Jordan is playing craps which requires a pair of dice. When playing craps, both dice are thrown and their outcomes are added.

two dies on a blue background
 How many possible outcomes does the sample space contain?
What is the probability of Jordan rolling an even outcome?
What is the probability that the difference between the number of dots on the dice is
Calculate the probability of rolling the most likely outcome.

Let's draw all the possible combinations when rolling two dice.

There are multiple combinations that add up to the same number. Remember, we cannot count an outcome multiple times. Therefore, the sample space is as follows. {2,3,4,5,6,7,8,9,10,11,12} The sample space has 11 outcomes.

To determine the probability of rolling an even number, we will highlight all even combinations in the table made earlier. Remember, an even number is divisible by 2.

We see that 18 combinations are even. Since the sample space is 6 by 6, the total number of possible combinations is 6* 6= 36. Now we can calculate the probability by dividing the number of favorable combinations by the number of possible combinations. P=18/36= 1/2 The probability of rolling an even number is 12.

Let's list all of the dice combinations that give a difference of 3. & Die 1-Die 2 [-1.1em] &D1 - D2 = 4-1 = 3 &D1 - D2 = 5-2 = 3 &D1 - D2 = 6-3 = 3 [1em] & Die 2-Die 1 [-1.1em] &D2 -D1 = 4-1 = 3 &D2 -D1 = 5-2 = 3 &D2 -D1 = 6-3 = 3 Let's highlight all of these combinations in the table we made earlier.

Of the 36 possible combinations, 6 of them give a favorable outcome. Now we can calculate the probability that the difference between the dice is 3. P=6/36= 1/6

The most likely outcome is the number in the sample space that occurs most frequently. If we again look at the table with all the possible combinations for the dice, we see that 7 is the most frequent outcome.

There are 6 different combinations that give a seven. With this information, we can calculate the probability of rolling this outcome. P=6/36= 1/6

A manufacturer of computers tests computers and finds that of them have defects.

a computer with some code on the screen
 What is the probability that a computer chosen at random has a defect? Write you answer as a percentage.
Assuming the same proportion is maintained no matter the number of computers, predict the number of computers with defects in a shipment of

From the exercise, we know that of the 2000 computers tested, 8 have defects. If we divide the number of defective computers by the total number of tested computers, we get the probability of a computer having a defect.

Consequently, there is a 0.4 % chance that a computer picked at random has a defect.

To predict the number of computers with defects in a shipment of 100 000, we must multiply the probability found earlier by the number of computers in the shipment. 100 000(0.004)=400 About 400 computers in the shipment could be defective.

Find the total number of possible outcomes for each of the following situations.

A card is drawn from a standard deck of cards.

We flip a coin and draw a marble from a bag containing two purple marbles and one gold marble.

We draw three marbles, one at a time and without replacing them, from a bag containing three green marbles and four blue marbles.

A standard deck has 52 playing cards. Therefore, the number of possible outcomes when drawing a card from one is 52.

In this case, we have a coin and a bag of marbles. A coin has two outcomes, heads and tails. This produces two outcomes.

Next up, we have to choose a marble. This can be purple or gold. Notice that we are not concerned with probabilities to figure out the possible outcomes. Only the number of possible outcomes is important, which means we will disregard the fact that there are more purple marbles than gold marbles in the bag.

Therefore, the number of possible outcomes in the sample space is 4. {H, P}, {H, G }, {T, P}, {T, G}

As in the previous situation, we are not concerned with probabilities at this point. Rather, we want to list all the possible outcomes. We can make another tree diagram to show all the possibilities.

As we can see, we have a total of 8 possible outcomes. {G, B, B}, {G, B, G}, {G, G, B}, {G, G, G}, {B, B, B}, {B, B, G}, {B, G, B}, {B, G, G}

Jordan rolls a regular six-sided die.

a regular six-sided red die

Calculate the probability of the following events happening. Write the answers as a fraction.

To calculate the probability of an event, we have to divide the number of favorable outcomes by the number of possible outcomes. P=Number of favorable outcomes/Number of possible outcomes In this case, Jordan has a regular six-sided die and we want to find the probability of her rolling at least a 2. This means we cannot roll a 1.

We have 5 favorable outcomes of 6 possible outcomes. Now we can determine the probability. P(At least a2)=5/6

Let's find all the possible even outcomes on a die.

We have 3 favorable outcomes out of 6 possible outcomes. Now we can determine the probability. P(Even)=3/6=1/2

The urn below contains three red, four blue, and five yellow balls.

an urn with red, blue, and yellow balls

Kriz pulls out a ball without looking. Give the probability as a fraction that the ball is...

Probability is calculated by dividing the number of favorable outcomes by the number of possible outcomes. P=Number of favorable outcomes/Number of possible outcomes We have 4 blue balls, 3 red balls, and 5 yellow balls. blue balls:& && 4 red balls:& && 3 yellow balls:& && 5 [-1.2em] total:& &&12 We want to know the probability of picking a blue ball. With the given information, we can determine the probability of picking a blue ball. P( Blue) = 4/12=1/3

This time, we must divide the sum of the blue and yellow balls by the total number of balls. From the previous section we know that 4 balls are blue and 5 are yellow, for a total of 9 balls. Now we can determine the probability. P(BlueorYellow) = 9/12=3/4 The probability of picking a blue or a yellow ball is 34.

The event of picking a ball that is neither blue nor yellow is the complement of picking a blue or yellow ball. We already calculated the probability of picking a blue or yellow ball in the previous section. P(Blue or Yellow) = 3/4 Therefore, the probability of picking a ball that is neither blue nor yellow can be found using the complement rule.

The probability of picking a ball that is neither blue nor yellow is 14.

Consider the following probabilities:
Pair these probabilities with the likelihood of the following statements. Note that the given probabilities are not necessarily representative of the statement.

Let's think about the statements one at the time.

i. A Person With a High Income Went to College

A person does not have to have gone to college to have a high income. However, it still increases the possibility of securing a high-paying job if they have. The most appropriate probability would be 0.7. This is completely arbitrary, by the way — someone can definitely succeed without having gone to college!

ii. An Ant Can Fly a Jet

Ants are not able to fly a jet created for a human. The probability of this is therefore 0.

iii. A Card Dealer Deals the Ace of Spades

The ace of spades is one card out of 52 cards in a standard deck. To calculate the probability of being dealt this card, we divide 1 by 52. P=1/52≈ 0.02 The probability is about 0.02.

iv. Flipping a Coin Gives Either Heads or Tails

There are two possible outcomes when we flip a coin, either heads or tails. Therefore, the probability of either of them happening must be 1.

In a lottery there are three types of tickets.
Let represent the event that a person wins What is the complement to this event?

If the person does not win $10, they will have drawn either a no prize ticket or a $20 prize ticket. They therefore have the following complement. $20 prize and No prize

The Basics of Event Probability

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