Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
4. Compositions of Isometries
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Exercise 38 Page 575

Can â–³HGF be mapped onto â–³KJN just by translating â–³HGF? Is there a line of symmetry between â–³HGF and â–³KJN?

Transformation: Rotation
Center: (0,2)
Angle: 180^(∘)

Practice makes perfect

We will identify the mapping as a translation, reflection, rotation, or glide reflection. Then we will write a rule for the transformation. Let's do it!

Identifying the Transformation

In the given diagram, we want to identify the transformation that maps â–³HGF onto â–³KJN.

The transformation is not a translation because we cannot map â–³HGF onto â–³KJN by just moving â–³HGF while maintaining its orientation. Moreover, the transformation is not a reflection because there is no line of symmetry between â–³HGF and â–³KJN. This mapping looks like a rotation.

Writing the Rule

Let's start by finding the center of rotation. To do so, we will connect with line segments the corresponding vertices of the preimage and image. The point of intersection of these segments will be the center of rotation.

The point (0,2) is the center of rotation. The angle of rotation seems to be 180^(∘). Recall that unless we are specifically told otherwise, rotations are performed counterclockwise. Let's confirm these two things!



We can see that the transformation that maps △HGF onto △KJN is a rotation 180^(∘) about point (0,2). This can be written as r_((180^(∘), (0,2)))( △HGF)= △KJN.