Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
4. Compositions of Isometries
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Exercise 48 Page 576

Start with grouping the statements in all possible combinations and try to find an example for each group.

Statements I and III.

Practice makes perfect

We have been given the following three statements. I. In right &△ ABC, m∠ B = 90. II. In right &△ ABC, m∠ A = 80. III. In right &△ ABC, m∠ C = 90. In order to identify the two statements that contradict each other, we will first group the statements in all possible combinations.

Group A Group B Group C
I. In right △ ABC, m∠ B = 90. I. In right △ ABC, m∠ B = 90. II. In right △ ABC, m∠ A = 80.
II. In right △ ABC, m∠ A = 80. III. In right △ ABC, m∠ C = 90. III. In right △ ABC, m∠ C = 90.

Next, we will find an example for each group. If we cannot, we will try to verify whether the statements contradict each other or not. Let's start with Group A.

Group A

An example for Group A must be a right triangle with m∠ B = 90 and m∠ A = 80. By the Triangle Angle-Sum Theorem, the interior angles of a triangle must add up to 180^(∘). m∠ A + m∠ B + m∠ C = 180 To find m∠ C, let's substitute m∠ A = 80 and m∠ B = 90 in the above equation.
m∠ A + m∠ B + m∠ C = 180
80+ 90+m∠ C=180
170+m∠ C=180
m∠ C=10
Let's draw the obtained triangle.

We can see that it is possible to have a right triangle with an interior angle m∠ 80. Therefore, statements I and II do not contradict each other.

Group B

Let's continue with Group B. We are trying to find a right triangle with two right-angles. We will apply the Triangle Angle-Sum Theorem. m∠ A + m∠ B + m∠ C = 180 To find m∠ A, let's substitute m∠ B = 90 and m∠ C = 90 in the above equation.
m∠ A + m∠ B + m∠ C = 180
m∠ A + 90+ 90=180
m∠ A + 180=180
m∠ A = 0
Therefore, it is not possible to give an example of a triangle and that has two right angles. Statements I and III contradict each other.

Group C

For the last group, like the Group A, we will examine the angles m∠ A =80 and m∠ C = 90. By the Triangle Angle-Sum Theorem, the interior angles of a triangle must add to 180^(∘). m∠ A + m∠ B + m∠ C = 180 To find m∠ B, let's substitute m∠ A = 80 and m∠ C = 90 in the above equation.
m∠ A + m∠ B + m∠ C = 180
80+m∠ B + 90=180
170+m∠ B=180
m∠ B=10
Let's draw the obtained triangle.

Since we are able to have a triangle with the given angles, statements II and III do not contradict each other.