Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
5. Circles in the Coordinate Plane
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Exercise 35 Page 801

Use the Distance Formula to calculate the radius of the circle.

(x-2)^2+(y-2)^2=16

Practice makes perfect
To begin, let's recall the Distance Formula. It is used to find the distance d between two points (x_1,y_1) and (x_2,y_2). d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2) We will find the radius of our circle by substituting its center and one point through which the circle passes into this formula and finding the distance between these two points. Let's look at the graph to identify the coordinates of these points.
The center has the coordinates (2,2). We can also tell that the circle passes through the point (2,6). Now we are ready to use the Distance Formula. Let's do it!
d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2)
d=sqrt(( 2- 2)^2+( 2- 6)^2)
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Evaluate right-hand side
d=sqrt(0^2+(-4)^2)
d=sqrt(0+16)
d=sqrt(16)
d=4
Let's now recall the standard form of an equation of a circle. (x- h)^2+(y- k)^2= r^2 In this formula, ( h, k) is the center of the circle and r is its radius. We have already found that the center of the circle is ( 2, 2). This information, together with r= 4, is enough to write the equation. (x- 2)^2+(y- 2)^2= 4^2 ⇕ (x-2)^2+(y-2)^2=16