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Pearson Geometry Common Core, 2011

PG

Pearson Geometry Common Core, 2011 View details

5. Circles in the Coordinate Plane

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Exercise 3 Page 800

Adapt the given equation to match the standard equation of a circle.

Center: (8,0)
Radius: 3

Practice makes perfect

Let's start by recalling the standard equation of a circle. (x- h)^2+(y- k)^2= r^2 The center of the circle is the point ( h, k) and the radius is r. We will rewrite the given equation to match this form. After that, we can identify the center and the radius.

(x-8)^2+y^2=9

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Rewrite

Identity Property of Addition

(x-8)^2+(y+0)^2=9

Rewrite 0 as -0

(x-8)^2+(y-0)^2=9

Write as a power

(x- 8)^2+(y- 0)^2=( 3)^2

The center of the circle is the point ( 8, 0) and its radius is 3.

Subchapter links

Lesson Check p.800

Practice and Problem-Solving Exercises p.801-803

Standardized Test Prep p.803

Mixed Review p.803