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Pearson Geometry Common Core, 2011

PG

Pearson Geometry Common Core, 2011 View details

5. Circles in the Coordinate Plane

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Exercise 26 Page 801

Adapt the given equation to match the standard equation of a circle.

Center: (3,-8)
Radius: 10
Graph:

Practice makes perfect

Let's start by recalling the standard equation of a circle. (x- h)^2+(y- k)^2= r^2Here, the center is the point ( h, k) and the radius is r. We will rewrite the given equation to match this form, and then we can identify the center and the radius.

(x-3)^2+(y+8)^2=100

a+b=a-(- b)

(x-3)^2+(y-(-8))^2=100

Write as a power

(x- 3)^2+(y-( -8))^2= 10^2

The center of the circle is the point ( 3, -8) and its radius is 10. Finally, we can graph the circle using this information.

Subchapter links

Lesson Check p.800

Practice and Problem-Solving Exercises p.801-803

Standardized Test Prep p.803

Mixed Review p.803