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Pearson Geometry Common Core, 2011

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Pearson Geometry Common Core, 2011 View details

5. Circles in the Coordinate Plane

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Exercise 13 Page 801

What is the standard form of an equation of a circle?

(x+9)^2+(y+4)^2=5

Practice makes perfect

Let's start by recalling the standard form of an equation of a circle.

(x- h)^2+(y- k)^2= r^2 In this form, ( h, k) is the center of the circle and r is its radius. We are told that the center of the circle is ( -9, -4) and its radius is sqrt(5). This is enough information to write the equation. (x-( -9))^2+(y-( -4))^2=( sqrt(5))^2 ⇕ (x+9)^2+(y+4)^2=5

Subchapter links

Lesson Check p.800

Practice and Problem-Solving Exercises p.801-803

Standardized Test Prep p.803

Mixed Review p.803