Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
2. Chords and Arcs
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Exercise 7 Page 776

Use Theorem 12-5, and the fact that ∠ TFE and HFG as well as ∠ MKL and ∠ JKN are vertical angles.

Example Solution:
∠ TFE≅ ∠ HFG ≅ MLK ≅ JKN
TE≅ HG≅ ML≅ JN
TE≅ HG≅ ML≅ JN
TF≅ EG≅ MJ≅ NL

Practice makes perfect

It is given that the circles on the diagram are congruent.

As we can see, central angles ∠ TFE and ∠ MKL are congruent. Also, ∠ TFE and HFG, as well as ∠ MKL and ∠ JKN, are vertical angles. By the Vertical Angles Theorem these four angles are congruent. ∠ HFG≅ ∠ TFE≅ MLK ≅ JKN Let's now review what the Theorem 12-5 states.

Theorem 12-5

Within a circle or in congruent circles, congruent central angles have congruent arcs.

According to this theorem, chords TE, HG, ML, and JN are congruent. Next we can use Theorem 12-6.

Theorem 12-6

Within a circle or in congruent circles, congruent chords have congruent arcs.

Since chords TE, HG, ML, and JN are congruent, their arcs TE, HG, ML, and JN are also congruent. TE≅ HG≅ ML≅ JN Similarly, angles ∠ TFH and ∠ EFG, just as ∠ MKJ and ∠ NKL, are also vertical angles and therefore congruent.

Note that ∠ TFE and ∠ TFH and ∠ MKL and ∠ MKJ are two pairs of adjacent supplementary angles. In other words, the sum of their measures is 180^(∘). Since m∠ TFE=m∠ MKL, we can conclude the following. l m∠ TFE+m∠ TFH=180^(∘) m∠ MKL+m∠ JKM=180^(∘) ⇓ m∠ TFH=m∠ JKM All four angles — ∠ TFE, ∠ TFH, ∠ MKL, and ∠ MKJ — are congruent angles.

Now, let's recall Theorem 12-4.

Within a circle or in congruent circles, congruent central angles have congruent arcs.

By the theorem, arcs TF, EG, MJ, and NL are congruent arcs. TF≅ EG≅ MJ≅ NL