Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
Chapter Review
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Exercise 16 Page 753

185.6 ft^2

Practice makes perfect

The given solid is a cone.

To calculate the surface area of a cone, we can use the known formula where r is the radius of the base and l is the slant height of the cone. S=Ï€ rl+Ï€ r^2 We can see that the length of radius is 4ft. To find the slant height, we can use the Pythagorean Theorem. When doing this, the slant height l is the hypotenuse. The height of the cone and radius of the base are the legs. Let's use these given values to solve for l.

r^2+h^2=l^2
â–¼
Solve for l
4^2 + 10^2 = l^2
16 + 100 = l^2
116 = l^2
sqrt(116) = l
l = sqrt(116)

The length of the slant height is sqrt(116). Now we have all the information we need to calculate the surface area of the cone. By substituting r with 4 and l with sqrt(116) into the formula, we can calculate S. Let's do it!

S=Ï€ rl+Ï€ r^2
S=Ï€( 4)( sqrt(116))+Ï€( 4)^2
â–¼
Simplify right-hand side
S=Ï€(4sqrt(116))+16Ï€
S=(16+4sqrt(116))Ï€
S=185.60943...
S≈ 185.6

The surface area of the cone, to the nearest tenth, is 185.6ft^2.