The area of a regular polygon is half the product of the apothem and the perimeter. We will first find the apothem and then the side length to obtain the perimeter. Finally, we will use this information to find the area.
Let's do it!
Apothem
By drawing the six radii, we can divide the hexagon into six isosceles triangles. Since the triangles are congruent and a full turn measures 360^(∘), the central angles of the isosceles triangles formed by the radii measure 3606=60^(∘).
Now, let's consider just one of these isosceles triangles. We will also draw the apothem a of the hexagon, which is perpendicular to the side.
Remember that an apothem bisects the central angle and the side of the regular polygon. Therefore, we obtain a right triangle with an acute angle that measures 30^(∘).
By the Triangle Angle Sum Theorem we know that the sum of the three interior angles of a triangle add to 180^(∘). With this information we can find the measure of the unknown acute angle.
180- 90- 30=60^(∘)
The third angle of the right triangle measures 60^(∘). Therefore, we have a 30^(∘)-60^(∘)-90^(∘) triangle.
In this type of special triangle, the longer leg is sqrt(3)2 times the hypotenuse. Keep in mind that the longer leg of this triangle is the apothem of the polygon.
a=sqrt(3)/2 * 6sqrt(3)
Let's simplify the right-hand side of this equation to obtain the apothem.
Consider the 30^(∘)-60^(∘)-90^(∘) triangle one more time.
In this type of triangle, the shorter leg is half the length of the hypotenuse.
Shorter Leg: 6sqrt(3)/2=3sqrt(3)m
As previously mentioned, the apothem bisects the side of the regular hexagon. Therefore, the length of the side of the given polygon is twice the length of the side of the above triangle.
Consequently, the side length of the regular hexagon is 6sqrt(3)m. Since this polygon has six congruent sides, to find its perimeter we will multiply the side length by 6.
Perimeter: 6* 6sqrt(3)=36sqrt(3)m
Area
Now that we know that the apothem of the figure is 9m and that the perimeter is 36sqrt(3)m. To find its area, we will substitute these values in the formula A= 12ap. Let's do it!
