Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
3. Areas of Regular Polygons
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Exercise 50 Page 634

Use the formulas for perimeter and area of a rectangle.

Perimeter: 28in.
Area: 49in.^2

Practice makes perfect

Let's calculate the perimeter and area of the given figure separately. Notice that because all of its sides are congruent and one of the angles is a right angle, we have a square.

Perimeter

We are asked to find the perimeter of the given figure. In general, the perimeter of a figure is the sum of its side lengths. A square has 4 equal sides, so we can find its perimeter using the following formula. P=a+a+a+a ⇔ P=4a In this formula, a is the length of each side. From the picture, we know that a is equal to 7 inches. Substituting this value into the formula, we can calculate P.
P=4a
P=4( 7)
P=28
The square's perimeter is 28 inches.

Area

To find the area of the square, we will use the formula for calculating the area of a rectangle. A=l * w Since a square is a rectangle whose length l and width w are equal, we can adapt the formula for a square with side length s. A=l * w ⇒ A=s^2 We have been given that the side length s is equal to 7 inches. To find the area of the square, we will substitute this value into the formula to calculate A.
A=s^2
A= 7^2
A=49
The area of the square is 49 square inches.