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h(t)=-5t^2+7t
t= 0.7
Calculate power and product
Add terms
Therefore the vertex is ( 0.7, 2.45), which means the ball took 0.7 seconds to reach the maximum height of 2.45 meters from the point of the toss.
h(t) = -5t^2 + 7t = 0.6
LHS-0.6=RHS-0.6
Use the Quadratic Formula: a = -5, b= 7, c= -0.6
Calculate power and product
Subtract terms
Calculate root
Put minus sign in front of fraction
State solutions
(I), (II):Calculate quotient
We got two different times at which the ball was 0.6 meters from the point of the toss. From Part A, we know the ball reached the maximum height at 0.7 seconds. This means that at t_1=0.1 seconds the ball was going up, and at t_2=1.3 seconds the ball was going down.
In conclusion, the ball remained in the air for approximately 1.3 seconds between the toss and the serve.