5. Quadratic Equations
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What is the area of the painting with the frame? Without the frame? What happens if you subtract these two areas? Remember that the width of the frame is the same around the entire painting.
3 inches wide.
Let's begin by plotting the painting with the frame. Let x be the width of the frame. Our mission is finding the value of x.
Multiply
Add and subtract terms
Substitute a= 1, b= 20, c= -69
| x_(1,2) = -20 ± 26/2 | |
|---|---|
| x_1 = -20 + 26/2 | x_2 = -20 - 26/2 |
| x_1 = 3 | x_2 = -23 |
Since x represents the width's frame it cannot be negative, so we disregard the negative option. In conclusion, the width of the frame is 3in.