Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
5. Quadratic Equations
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Exercise 25 Page 229

First, rewrite the equation in standard form.

0.8, - 1

Practice makes perfect
To solve the equation using our calculator with a table, we first have to rewrite the equation in standard form.
5x^2+x=4
5x^2+x-4=0
Having rewritten the equation in standard form, we can enter it in the calculator by pushing Y= and typing it in the first row.
Window with inequality

Next, by pushing 2ND and GRAPH, we get a table of values for whole number inputs of x. We are looking for x-values that make the y-column equal 0.

Window with inequality

Note that x=- 1 provides a value of 0 in the y-column. From the table, we see that the function starts increasing somewhere between x=0 and x=1. Thus, a second solution should be between x=0 and x=1. To find its exact value, we will need to view smaller increments in the table. To change the table settings, push 2ND and then WINDOW. Then change the TblStart to 0.3 and â–ł Tbl to 0.1.

Window with inequality

Now push 2ND and GRAPH to see the table again with the new setup.

Window with inequality
Window with inequality

Now we know that x=0.8 and x=- 1 both provide a value of 0 in the y-column. These are the zeros of the function, so the solutions to the quadratic equation are x=0.8 and x=- 1.