Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
5. Quadratic Equations
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Exercise 62 Page 231

Write all the functions in standard form and look at their constant terms.

A

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The constant term of a quadratic function corresponds to the value of c, when the function is written in standard form. y=ax^2+bx + c We need to determine which of the given functions has a constant term equal to -3. Functions B and D are already written in standard form. Let's check their constant terms.
Function Constant Term Equal to -3?
B: y=x^2-3x+ 3 3 NO
D: g(x)=-3x^2+3x+ 9 9 NO
Looking at the table above, we can discard functions B and D. Now, let's rewrite the other two functions in standard form. To do that, we multiply the factors and simplify the resulting expression. Let's begin with option A.
y = (3x+1)(- x-3)
y = -3x^2 - 9x - x - 3
y = -3x^2 - 10x - 3
After simplifying, we see that the constant term of the latter function is -3. Therefore, the correct option is A. However, let's verify that option C is not correct.
f(x) = (x-3)(x-3)
f(x) = x^2-3x-3x+9
f(x) = x^2-6x+9
The constant term of the resulting function is 9. Option C is not correct.