Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
5. Quadratic Equations
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Exercise 24 Page 229

First, rewrite the equation in standard form.

- 0.75, 1

Practice makes perfect
To solve the equation using our calculator with a table, we first have to rewrite the equation in standard form.
4x^2=x+3
4x^2-x=3
4x^2-x-3=0
Having rewritten the equation in standard form, we can enter it in the calculator by pushing Y= and typing it in the first row.
Window with inequality

Next, by pushing 2ND and GRAPH, we get a table of values for whole number inputs of x. We are looking for x-values that make the y-column equal 0.

Window with inequality

From the table, we can see that x=1 provides a a value of 0 in the y-column. This is the first solution of the given equation. x=1 Note also that the y-values change signs from positive to negative. Thus, y must reach 0 when x is somewhere between - 1 and 0. To find the exact value, we will need to view smaller increments in the table. To change the table settings, push 2ND and WINDOW. Then change the TblStart to - 1 and â–ł Tbl to 0.01.

Window with inequality

Now push 2ND and GRAPH to see the table again with the new configurations.

Window with inequality

We can see that x=- 0.75 provides a value of 0 in the y-column. Thus, it is the second solution of the given equation. x=- 0.75